<span>Formula: H(t) = 56t – 16t^2
</span>
H(t) = - 16t^2 + 56t
<span><span>A.
</span>What is the height of the ball after 1 second? H
(1) = 56(1) – 16(1) ^2 = 40 pt.</span>
<span><span>B.
</span>What is the maximum height? X = - (56)/2(- 16) =
1.75 sec h (1.75) = 56(1.75) – 16(1.75) ^2 h (1.75) = 49ft.</span>
<span><span>C.
</span><span>After how many seconds will it return to the
ground? – 16t^2 + 56t = 0 - 8t =0 t = 0</span></span>
<span><span>-
</span><span>8t (2 + - 7) = 0 2t – 7 = 0 t = 7/2
Ans: 3.5 seconds</span></span>
Answer:
yes
Step-by-step explanation:
675
15*45
3*5 5*9
3*3
3^3*5^2=675
Answer:
B
Step-by-step explanation:
The <u>sample space</u> for this experiment is the set of all possible outcomes.
A student rolls a number cube whose six faces are numbered 1 through 6.
Therefore, all possible outcomes are:
- rolled number 1;
- rolled number 2;
- rolled number 3;
- rolled number 4;
- rolled number 5;
- rolled number 6.
Hence, the sample space is {1, 2, 3, 4, 5, 6}
