Answer:
= -32a+64b
Step-by-step explanation:
thats the answer
<h3><u>Question</u><u>:</u></h3>
<u>The difference between a 2-digit number and the number formed by reversing its digits is 45. If the sum of the digits of the original number is 13, then find the number. </u>
<h3><u>Statement</u><u>:</u></h3>
<u>The difference between a 2-digit number and the number formed by reversing its digits is 45. </u><u>T</u><u>he sum of the digits of the original number is 13</u><u>.</u>
<h3><u>Solution:</u></h3>
- Let one of the digit of the original number be x.
- So, the other digit = (13-x)
- Therefore, the two digit number = 10(13-x) + x = 130-10x+x = 130-9x
- The number obtained after interchanging the digits is 10x+(13-x) =9x+13
- Therefore, by the problem
130-9x-(9x+13) = 45
or, 130-9x- 9x-13 = 45
or, -18x = 45-130+13
or, -18x= -72
or, x = 72/18 = 4
or, x = 4
- So, the original number = 130-9x = 130 -9(4) = 130 - 36 = 94
<h3>Answer:</h3>
The number is 94.
I think the answer you have given isn't right. The answer should be 94.
3(3)^2 - (-2)^3 - (-2)^3 + 5
27 - (-8) - (-8) +5
35 - (-8) + 5
43 + 5
48
Answer: x=2
3x−9x+7−3=−8
Step 1: Simplify both sides of the equation.
3x−9x+7−3=−8
3x+−9x+7+−3=−8
(3x+−9x)+(7+−3)=−8
−6x+4=−8
−6x+4=−8
−6x+4−4=−8−4
−6x=−12
−6x
−6
=
−12
−6
x=2
