Adult ticket (a) = $5
Child ticket (c) = $2
785 tickets = $3280
a + c = 785 tickets
5a + 2c = $3280
c = 215 child tickets
a = 570 adult tickets
570 + 215 = 785 tickets
5(570) + 2(215) = $3280
There were 215 child tickets sold on Saturday
To get the *percent increase* from week 1 to week 2, we calculate the change in distance from week 1 to week 2 (13.5 - 12.5 = 1 mile) over the week 1 distance (12.5 miles). Doing that, we find that Matthew increased his distance by
1/12.5 = 0.08, or 8%
We’re given that he’ll increase his distance by the same percentage from week 2 to 3, so to find his week 3 distance, we can find 8% of the week 2 distance and add that on. 8% of 13.5 miles is 0.08 x 13.5 = 1.08 miles, so by week 3, he’ll be running 13.5 + 1.08 = 14.58 miles.
Answer:
one because it is cilinder
<h3>
Answer: log(2)</h3>
Explanation:
The rule to use here is log(x)-log(y) = log(x/y)
So,
log(6)-log(3) = log(6/3) = log(2)
