What is (1/0)^2+(22/3)
1 answer:
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So the answer is
------------------
I used the log rules
y*log(x) = log(x^y)
log(x) + log(y) = log(x*y)
these rules apply to any log base (not just base 10).
So the answer is
------------------
I used the log rules
y*log(x) = log(x^y)
log(x) + log(y) = log(x*y)
these rules apply to any log base (not just base 10).