Answer:
179.0 g of iridium (1 mol / 192.217 g) ( 6.022 x 10^23 atoms / 1 mol ) = 5.61 x 10^23 atoms of iridium
Explanation:
Atomic mass Carbon (C ) = 12.01 a.m.u
12.01 g ---------- 6.02x10²³ atoms
1.50 g ----------- ??
1.50 x ( 6.02x10²³ ) / 12.01 =
7.51x10²² atoms of C
hope this helps!
