Answer : 0.026 moles of oxygen are in the lung
Explanation :
We can solve the given question using ideal gas law.
The equation is given below.
We have been given P = 21.1 kPa
Let us convert pressure from kPa to atm unit.
The conversion factor used here is 1 atm = 101.3 kPa.
V = 3.0 L
T = 295 K
R = 0.0821 L-atm/mol K
Let us rearrange the equation to solve for n.
0.026 moles of oxygen are in the lung
Answer:
80ml
Explanation:
you have your initial concentration to be 0.25 mole on your final volume to be 250 ml and your final concentration to be 0.8 0.08 molar you don't have your initial volume sotify your initial volume you use the expression see 1 * 21 equals see two times between you make when when the subject then 1 equals to 2 x 2/3 one you know substitute your values into it to get being one that's your original volume to be at the latest or 80 ml
