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slava [35]
3 years ago
11

Chemist preformed Reaction of solid magnesium burning and found that the mass of the magnesium oxide what is greater than the ma

ss of the magnesium. What is the reason behind this increase in math reaction of solid magnesium burning and found that the mass of the magnesium oxide what is greater than the mass of the magnesium. What is the reason behind this increase in mass?
Chemistry
1 answer:
tankabanditka [31]3 years ago
4 0

Answer:

The magnesium reacted with the oxygen in the air.

Explanation:

For argument’s sake, let’s say that the mass of magnesium oxide was 3 g and that of the oxide was 5 g.  

The reaction was

            magnesium + oxygen ⟶ magnesium oxide

Mass:           3 g                                          5 g

Mass of oxygen = 5 g – 3 g = 2 g

The 3 g of magnesium must have combined with 2 g of oxygen to form 5 g of magnesium oxide.

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Answer:

Explanation:

CCl4 => C + 2Cl2

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Why is the water cycle called a cycle and not a system?
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It is called a cycle because it is repetitive, therefore making it a cycle (or almost never ending)
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3 years ago
Before we can use this equation for
AlexFokin [52]

Answer:

2C₂H₆ +  [7]O₂     →      [4]CO₂ + [6]H₂O

Explanation:

Chemical equation:

C₂H₆ +  O₂     →      CO₂ + H₂O

Balanced chemical equation:

2C₂H₆ +  7O₂     →      4CO₂ + 6H₂O

Step 1:

2C₂H₆ +  O₂     →      CO₂ + H₂O

Left hand side                      Right hand side

C = 4                                     C = 1

H = 12                                    H = 2

O = 2                                     O = 3

Step 2:

2C₂H₆ +  O₂     →      4CO₂ + H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 2

O = 2                                     O = 9

Step 3:

2C₂H₆ +  O₂     →      4CO₂ + 6H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 12

O = 2                                     O = 14

Step 4:

2C₂H₆ +  7O₂     →      4CO₂ + 6H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 12

O = 14                                     O = 14

3 0
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7 0
3 years ago
Compound A and Compound B are binary compounds containing only elements X and Y. Compound A contains 1.000 g of X for every 2.10
ycow [4]

Answer:

Explanation:

a) for 1.000 g X: 0.1621 g Y

ratio of mass of element Y = 2.100g : 0.1621g

= 1 : 0.07

b) 1.000 g X: 0.7391 g Y

ratio of mass of element Y = 2.100g : 0.7391g

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c) 1.000 g X: 0.2579 g Y

ratio of mass of element Y = 2.100g : 0.2579g

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d) 1.000 g X: 0.2376 g Y

ratio of mass of element Y = 2.100g : 0.2376g

= 1: 0.11

e) 1.000 g X: 0.2733 g Y

ratio of mass of element Y = 2.100g : 0.2733g

= 1 : 0.13

From the values obtained , the closest that is in compliance with the law f multiple proportions is option B

7 0
3 years ago
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