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slava [35]
3 years ago
11

Chemist preformed Reaction of solid magnesium burning and found that the mass of the magnesium oxide what is greater than the ma

ss of the magnesium. What is the reason behind this increase in math reaction of solid magnesium burning and found that the mass of the magnesium oxide what is greater than the mass of the magnesium. What is the reason behind this increase in mass?
Chemistry
1 answer:
tankabanditka [31]3 years ago
4 0

Answer:

The magnesium reacted with the oxygen in the air.

Explanation:

For argument’s sake, let’s say that the mass of magnesium oxide was 3 g and that of the oxide was 5 g.  

The reaction was

            magnesium + oxygen ⟶ magnesium oxide

Mass:           3 g                                          5 g

Mass of oxygen = 5 g – 3 g = 2 g

The 3 g of magnesium must have combined with 2 g of oxygen to form 5 g of magnesium oxide.

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Answer:

352

Explanation:

.75 times 472 because .25 is sugar so .75 is watet

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3 years ago
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Answer:

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4 0
3 years ago
Analysis of a compound indicates that it contians 1.04 g K, 0.70 g Cr, and 0.86 g O. Find its empirical formula.
Annette [7]

Answer:

K2CrO4

Explanation:

To find the empirical formula, we need to divide each element by its atomic mass. The atomic masses of potassium, chromium and oxygen are 39.0983, 51.9961 and 15.999 respectively. We make the divisions as follows:

K = 1.04/39.0983 = 0.027

Cr = 0.70/51.9961 = 0.013

O = 0.86/15.999 = 0.054

We now divide by the smallest which is the number of moles of the Chromium

K = 0.027/0.013 = 2

Cr = 0.013/0.013 = 1

K = 0.054/0.013 = 4 approximately

The empirical formula is thus:

K2CrO4

7 0
3 years ago
You already converted mass to moles for the reactants now convert mass to moles for the product, copper 0.71 g Cu equals
skelet666 [1.2K]

Answer: 0.011 moles.

Explanation:-

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

Given :

Mass of copper = 0.71 g

Molar mass of copper = 63.5 g/mol

Putting i the values, we get:

\text{Number of moles of copper}=\frac{0.71g}{63.5g/mol}=0.011moles

Thus the number of moles of copper in 0.71 g of copper is 0.011 moles.

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4 years ago
PLZZ HELP!! If light traveling through air is then passed through glass, what is the result?
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