The answer to your question is y= -2/5x + 8/5
Time taken=distance/speed=125/65=1.92hoursprecisely 1hr55mins12secs
![r=\dfrac{12}{4+8\sin\theta}=\dfrac3{1+2\sin\theta}](https://tex.z-dn.net/?f=r%3D%5Cdfrac%7B12%7D%7B4%2B8%5Csin%5Ctheta%7D%3D%5Cdfrac3%7B1%2B2%5Csin%5Ctheta%7D)
Let
![y=2\sin\theta](https://tex.z-dn.net/?f=y%3D2%5Csin%5Ctheta)
, and recall that in polar coordinates,
![r=\sqrt{x^2+y^2}](https://tex.z-dn.net/?f=r%3D%5Csqrt%7Bx%5E2%2By%5E2%7D)
. This means you have
![\sqrt{x^2+y^2}=\dfrac3{1+y}](https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E2%2By%5E2%7D%3D%5Cdfrac3%7B1%2By%7D)
You can stop there, or try to find something that looks somewhat nicer.
In what ways do advertisers<span> in </span>magazines use sexual imagery<span> to </span>appeal<span> to </span>youth<span>? </span>One study classified each<span> of </span>1500 full-page<span> or </span>larger ads<span> as "</span>not sexual<span>" or ..</span>
What are the different statements