3 years ago

If f(x)=3x^2+1 and g(x) =1-x, what is the truly value of (f-g)(2)

Mathematics

1 answer:

Lilit [14]3 years ago

8 0

Answer:

Step-by-step explanation:

f(x)=3x²+1

f(2) = 3 x 2² + 1 = 13

g(x) =1-x

g(2) = 1 - 2 = -1

(f-g)(2) f(2) - g(2) = 13 - (-1) = 14

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