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2 years ago

The low temperature on a certain day is 51°F. The low temperature is 17°F lower than the high temperature, h.

1 answer:

5 0

Using the change of subject of formula, the high temperature value for the day can be modeled using the expression High temperature = Low temperature - 17°F

Giveb the Parameters :

Low temperature = 51°F

The low temperature is 17°F lower than the high temperature, this can be modeled as an equation thus :

Low temperature = High temperature + 17°F

Male the high temperature the subject :

High temperature = Low temperature - 17°F

Therefore, the equation which models the high temperature is : High temperature = Low temperature - 17°F

Learn more :brainly.com/question/25449918

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x = 22.

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2 years ago

John's commute to work is 20kmhr while Sheri's commute is 500mmin. Who has the fastest commute to work in mihrif 1.61km=1mi? A S

Andreyy89

Answer:

A) Sheri has the faster commute by 6.2 miles/hr.

Step-by-step explanation:

Given

John's commute to work $=20\ km/hr$

Sheri's commute to work $=500\ m/min$

$1.61\ km = 1\ mile$

John's commute to work in miles per hour = $\frac{20\ km}{1 hr}\times \frac{1\ mile}{1.61\ km}= 12.42\ miles/hr$

Sheri's commute to work in miles per hour = $\frac{500\ m}{1\ min}\times \frac{1\ km}{1000\ m}\times \frac{1\ mile}{1.61\ km}\times \frac{60\ min}{1\ hr}= 18.63\ miles/ hr$

We can see that Sheri has a faster commute.

Difference between the rates = $18.63\ miles/ hr-12.42\ miles/hr=6.21\ miles/hr\approx 6.2\ miles/hr$

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