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Strike441 [17]
3 years ago
6

The low temperature on a certain day is 51°F. The low temperature is 17°F lower than the high temperature, h.

Mathematics
1 answer:
ohaa [14]3 years ago
5 0

Using the change of subject of formula, the high temperature value for the day can be modeled using the expression <em>High temperature = Low temperature - 17°F</em>

<u>Giveb</u><u> </u><u>the</u><u> </u><u>Parameters</u><u> </u><u>:</u>

  • <em>Low</em><em> </em><em>temperature</em><em> </em><em>=</em><em> </em><em>51</em><em>°</em><em>F</em>

<u>The</u><u> </u><u>low</u><u> </u><u>temperature</u><u> </u><u>is</u><u> </u><u>17</u><u>°</u><u>F</u><u> </u><u>lower</u><u> </u><u>than</u><u> </u><u>the</u><u> </u><u>high</u><u> </u><u>temperature</u><u>,</u><u> </u><u>this can be</u><u> </u><u>modeled</u><u> </u><u>as</u><u> </u><u>an</u><u> </u><u>equation</u><u> </u><u>thus</u><u> </u><u>:</u>

<em>Low temperature = High temperature + 17°F</em>

<u>Male</u><u> </u><u>the</u><u> </u><u>high</u><u> </u><u>temperature</u><u> </u><u>the</u><u> </u><u>subject</u><u> </u><u>:</u>

High temperature = Low temperature - 17°F

Therefore, the equation which models the high temperature is : <em>High temperature = Low temperature - 17°F</em>

Learn more :brainly.com/question/25449918

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Step-by-step explanation:

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The length of a rectangle is 3 more inches than the width. Find the length and width of the rectangle is the perimeter of the re
n200080 [17]

Part A:

Let the width of the rectangle be = x inches

As given, the length of a rectangle is 3 more inches than the width so let the length of the rectangle be = x+3 inches

Perimeter is given as = 54 inches

Perimeter = 2(l+b)

Equation becomes:

2(x+3+x)=54

2(2x+3)=54

Part B:

Solving the equation we get

4x+6=54

4x=54-6

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Hence, the width of the rectangle is 12 inches

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3 years ago
2. In how many ways can 3 different novels, 2 different mathematics books and 5 different chemistry books be arranged on a books
insens350 [35]

The number of ways of the books can be arranged are illustrations of permutations.

  • When the books are arranged in any order, the number of arrangements is 3628800
  • When the mathematics book must not be together, the number of arrangements is 2903040
  • When the novels must be together, and the chemistry books must be together, the number of arrangements is 17280
  • When the mathematics books must be together, and the novels must not be together, the number of arrangements is 302400

The given parameters are:

\mathbf{Novels = 3}

\mathbf{Mathematics = 2}

\mathbf{Chemistry = 5}

<u />

<u>(a) The books in any order</u>

First, we calculate the total number of books

\mathbf{n = Novels + Mathematics + Chemistry}

\mathbf{n = 3 + 2 +  5}

\mathbf{n = 10}

The number of arrangement is n!:

So, we have:

\mathbf{n! = 10!}

\mathbf{n! = 3628800}

<u>(b) The mathematics book, not together</u>

There are 2 mathematics books.

If the mathematics books, must be together

The number of arrangements is:

\mathbf{Maths\ together = 2 \times 9!}

Using the complement rule, we have:

\mathbf{Maths\ not\ together = Total - Maths\ together}

This gives

\mathbf{Maths\ not\ together = 3628800 - 2 \times 9!}

\mathbf{Maths\ not\ together = 2903040}

<u>(c) The novels must be together and the chemistry books, together</u>

We have:

\mathbf{Novels = 3}

\mathbf{Chemistry = 5}

First, arrange the novels in:

\mathbf{Novels = 3!\ ways}

Next, arrange the chemistry books in:

\mathbf{Chemistry = 5!\ ways}

Now, the 5 chemistry books will be taken as 1; the novels will also be taken as 1.

Literally, the number of books now is:

\mathbf{n =Mathematics + 1 + 1}

\mathbf{n =2 + 1 + 1}

\mathbf{n =4}

So, the number of arrangements is:

\mathbf{Arrangements = n! \times 3! \times 5!}

\mathbf{Arrangements = 4! \times 3! \times 5!}

\mathbf{Arrangements = 17280}

<u>(d) The mathematics must be together and the chemistry books, not together</u>

We have:

\mathbf{Mathematics = 2}

\mathbf{Novels = 3}

\mathbf{Chemistry = 5}

First, arrange the mathematics in:

\mathbf{Mathematics = 2!}

Literally, the number of chemistry and mathematics now is:

\mathbf{n =Chemistry + 1}

\mathbf{n =5 + 1}

\mathbf{n =6}

So, the number of arrangements of these books is:

\mathbf{Arrangements = n! \times 2!}

\mathbf{Arrangements = 6! \times 2!}

Now, there are 7 spaces between the chemistry and mathematics books.

For the 3 novels not to be together, the number of arrangement is:

\mathbf{Arrangements = ^7P_3}

So, the total arrangement is:

\mathbf{Total = 6! \times 2!\times ^7P_3}

\mathbf{Total = 6! \times 2!\times 210}

\mathbf{Total = 302400}

Read more about permutations at:

brainly.com/question/1216161

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Step-by-step explanation:

For every 3x it travels 1 y so you will get 1/3 as your answer.

At 50y the line is at 10x.  By the time it is at 60 y it is at 40x.  This was a change in y by 10 and change in x by 30.  There fore the answer is 10/30 or 1/3.

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3 years ago
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