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3 years ago

Pictures, x

Mathematics

1 answer:

masha68 [24]3 years ago

3 0

Wat fraction post a pic of the problem

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If (x - c)^k is a factor of p(x), then c is a zero of p(x) with multiplicity k.

ivolga24 [154]

Answer:

True

Step-by-step explanation:

$plug \: c = x \: in \: (x - c)^{k} \\ (x - x)^{k} = (0)^{k} = 0$

8 0

3 years ago

The College Board provided comparisons of Scholastic Aptitude Test (SAT) scores based on the highest level of education attained

poizon [28]

Answer:

a. $H_{0}:$ u1≤u2

$H_{a} :u1>u2$

b P<0.05 rejected H

Step-by-step explanation:

College High School

485 442

534 580

650 479

554 486

550 528

572 524

497 492

592 478

487 425

533 485

526 390

410 535

515

578

448

469

The mean is the average . the sum of number over the number of observation

x1=525

x2=487

s.d1=59.42

s.d2=51.74

n1=16

n2=12 $\alpha =0.05$

Determine the hypothesis

$H_{0}:$ u1≤u2

$H_{a} :u1>u2$

find the degree of freedom $(\frac{s1^2}{n1} +\frac{s2^2}{n2} )^2/(\frac{s1^2}{n1} )^2/n1-1+(s2^2/n2)^2/n2-1\\\\(\frac{59.42^2}{16} +\frac{51.7476^2}{12} )^2/(\frac{59.42^2}{16} )^2/16-1+(51.74^2/12)^2/12-1$

p-value is the probability of obtaining the value of the test statistics. In the column of t-value in the row df=25

0.025<P<0.05

if the P value is actually less than or the same as the significant level, then the null hypothesis is rejected

P<0.05 rejected H

8 0

3 years ago

Hello, how are you? I hope you are well. I wanted to ask you if you could help me answer these divisions? Please I would really

Bogdan [553]

I
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6 0

3 years ago

(a) It takes the Earth 365 days to complete a full orbit around the sun. It takes Jupiter approximately 4,332 days, 14 h, and 9

kogti [31]

1 year = 365 days.

1 day = 24 hours.

1 hour = 60 minutes.

First convert the hours and minutes in Jupiter orbit to days:

14*60 = 840 +9 = 849 minutes.

849 / 60 = 14.15 hours.

14.15 / 24 = 0.59 days.

Jupiter's orbit is 4332.59 days.

Now divide that by 365 for the number of years:

4332.59 / 365 = 11.87 years.

5 0

3 years ago

What is the lateral area of a right cylinder if the radius of the base is 12 mm and the altitude of the cylinder is 5 times the

schepotkina [342]

Lateral Area of a cylinder is ; 2πR.H

R=12 mm and H= 15 mm

Then LATERAL area = 2π(12)(15) =48π ≈ 150 mm²

5 0

3 years ago