It's a simple linear equation in 'y'. There is only one number that 'y' can be
that will make the equation a true statement. That number is called the
'solution' to the equation. Here's one way to find it:
You said that <u> 2 = y/5 - 8</u>
Add 8 to each side: 10 = y/5
Multiply each side by 5: <em> 50 = y</em>
Answer:
A. Y-68=-5(x-14)
Step-by-step explanation:
Mary is spending money at the average rate of $5 per day. After 14 days she has $68 left. The amount left depends on the number of days that have passed. write an equation for the situation
We find the equation using the point slope equation of a line. This is given as:
y - y1 = m(x-x1)
The slope intercept form will be
y = -5x + b
since the amount decreases by $5 per day...
Our slope is -5 so m=-5
We have a point (x1,y1) = (14, 68)
Hence, we have:
y-68 = -5(x-14)
Option A is correct
Solve using equations:
Gina 11 = a+b+c
Sam 27 = 2a+3b+2c
Robby 19= a+2b+2c
Gina *2 give 22=2a+2b+2c (subtract this from Sam to give)
b=5
the subtract Robby from Gina *2 to give a=3
[Question 1]
let d = number of dramas Gina rented, c = # of comedies, and t = # of documentaries:
[equation a] d + c + t = 11
[equation b] 2d + 3c + 2t = 27
[equation c] d + 2c + 2t = 19
if we subtract [a] from [c] we get:
[equation d] c + t = 8
if we subtract [c]*2 from [b] we get:
[equation e] -c - 2t = -11 or
[equation e] c + 2t = 11
Now we can subtract [e] from [d] to solve for t:
t = 3
Now put in 3 for t in [d] or [e] to solve for c:
c + 2(3) = 11
c + 6 = 11
c = 5
So she rented 5 comedies and 3 documentaries which leaves 3 dramas (which is answer A)
Using the quadratic formula works but if you know there are 2 answers (highest power of problem tells you how many solutions) then
10x^2 = 5x
So either x = 0, giving 0=0. Or divide by 5x
2x = 1
x = 0.5
Answer:
a=1 or a=5/6
Step-by-step explanation:
I'm going to attempt to factor 6a^2-a-5
a=6
b=-1
c=-5
Find two numbers that multiply to be a*c and add to be b.
a*c=-30 =-6(5)
b=-1 =-6+5
So replace -a with -6a+5a in the expression we started with
6a^2-6a+5a-5
now we factor by grouping
6a(a-1)+5(a-1)
(a-1)(6a-5)
Now let's solve the equation:
(a-1)(6a-5)=0
So a=1 or a=5/6