Answer:
ANS. => none of the above
Answer:

Step-by-step explanation:
Given line = 30x - 5y = 5 or y = 6x + 1
so, the slope of the given line is 6.
now, let the line which is perpendicular to the given line be y = mx + c
where,
m = slope of the line
c = constant
As we know, if two lines are perpendicular to each other, the value of product of there slopes are -1.
so, slope of given line × slope of perpendicular line = -1
⇒ 6(m) = -1
⇒ m = 
By substitutiong the value of m in the equation, we get;
⇒ 
For c,
as the point (0,-3) passes through the line, we get;
⇒ 
⇒ 
Hence,
The line which is perpendicular to the given line and passes through (0,-3) is
.
Answer:
E. - 7
Step-by-step explanation:
2x2-X2+5X-10-4=0
X2+5X-14=0
X2-2X+7X-14.=0
X(X-2). 7(X-2)=0
(X+7). (X-2)
X=-7, X=2