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3 years ago

The product of (-5xy2) and (-4x2y)

Mathematics

1 answer:

solong [7]3 years ago

3 0

Combine like variables:

(20x^2)(2y^3)

Combine coefficients:

40(x^2)(y^3)

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A radio station sells buttons and bumper stickers at a local fair. The buttons cost $2.95 each, and the bumper stickers cost $3.

MA_775_DIABLO [31]

you question isn't quite clear.....

3 0

3 years ago

Ray industries bought a touchscreen monitor for $1200 it is expected to depreciate at a rate of 25% per year what was the value

max2010maxim [7]

So for this problem, we will be using the exponential equation format, which is y = ab^x. The a variable is the initial value, and the b variable is the growth/decay.

Since our touchscreen starts off at a value of 1200, that will be our a variable.

Since the touchscreen is decaying in value by 25%, subtract 0.25 (25% in decimal form) from 1 to get 0.75. 0.75 is going to be your b variable.

In this case, time is our independent variable. Since we want to know the value 3 years from now, 3 is the x variable.

Using our info above, we can solve for y, which is the cost after x years.

$y=1200*0.75^3\\y=506$

In context, after 3 years the touchscreen will only be worth $506.

7 0

3 years ago

What is the solution to this systems of equation? 2x-3y=9 and 5x+3y=10

mamaluj [8]

y = -5x/3 + 10/3

y = 2x/3 - 3

8 0

3 years ago

What is the value of y in the product of powers below? 8^3x8^-5x8^y=8^-2=1/8^2

Ber [7]

The answer is y=207 hope this helps

4 0

3 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .

Observe the image below.

7 0

3 years ago