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wlad13 [49]
4 years ago
13

Solve the simultaneous equations 2x+3y=-3 3x-2y=28

Mathematics
1 answer:
icang [17]4 years ago
4 0
\left \{ {\big{ 2x+3y=-3\ /\cdot2} \atop\big {3x-2y=28\ /\cdot3 }} \right.\\\\  \left \{ {\big{ 4x+6y=-6} \atop\big {9x-6y=84 }} \right.\\---------\\4x+9x=-6+84\\\\13x=78\ /:13\\\\x=6\\\\2x+3y=-3\ \ \ \ \Rightarrow\ \ \ 2\cdot6+3y=-3\ \ \ \Rightarrow\ \ \ 3y=-3-12\\\\3y=-15\ /:3\\\\c=-5\\\\Ans.\  \left \{ {{x=6} \atop {y=-5}} \right.
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Answer:

7 + 3/8x

Step-by-step explanation:

8+7/8x−1−1/2x.

Combine like terms

8-1  +  7/8x -1/2x

7 + 7/8x -1/2x

Get a common denominator

7 + 7/8x -4/8x

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7 0
3 years ago
An example of a "golden rectangle” has a length equal to x units and a width equal to x – 1 units. Its area is 1 square unit. Wh
Llana [10]
Area=length times width


area=1=x times (x-1)

1=x(x-1)
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0=x^2-x-1
using quadratic formula
for
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x= \frac{-b+/- \sqrt{b^2-4ac} }{2a}
for
0=1x^2-1x-1
a=1
b=-1
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x= \frac{-(-1)+/- \sqrt{(-1)^2-4(1)(-1)} }{2(1)}
x= \frac{1+/- \sqrt{1+4} }{2}
x= \frac{1+/- \sqrt{5} }{2}

x= \frac{1+ \sqrt{5} }{2} or x= \frac{1- \sqrt{5} }{2}
the 2nd one will be negative so we reject that because we can't have negative lengths

so
x= \frac{1+ \sqrt{5} }{2}
the length is \frac{1+ \sqrt{5} }{2}
8 0
3 years ago
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lora16 [44]

Answer:

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Step-by-step explanation:

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3 years ago
10% more than 4 is what​
Helen [10]

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Step-by-step explanation:

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7 0
1 year ago
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tensa zangetsu [6.8K]
C=5 that is the answer
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3 years ago
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