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3 years ago

Compare the y-intercepts and the rates of change of the following items.

Mathematics

2 answers:

Virty [35]3 years ago

5 0

The y-intercepts are the same, but the rates of change are different.

liberstina [14]3 years ago

5 0

Answer: The correct option is

(C) The y-intercepts are the same, but the rates of change are different.

Step-by-step explanation: We are given to compare the y-intercepts and the rates of change of the given items.

For item I :

The given equation of the line is in slope-intercept for, as follows :

$y=2x-4.$

So, the y-intercept of the line is -4 and the rate of change is given by the slope of the line, i.e., 2.

For item II :

We see that

at x = 0, the value of y is -4. So, the y-intercept of the linear function (a line) is -4.

Now, (-4, -6) and (-2, -5) are two points on the line, so the rate of change will be

$R=\dfrac{-5-(-6)}{-2-(-4)}=\dfrac{1}{2}.$

Therefore, the y-intercepts are same but rate of changes are different.

Thus, (C) is the correct option.

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1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n

Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

70% of fatalities involve an intoxicated driver, hence $p = 0.7$ .

A sample of 15 fatalities is taken, hence $n = 15$ .

The probability is:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

Hence

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061$

$P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186$

$P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700$

$P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916$

$P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305$

$P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047$

Then:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215$

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0

3 years ago

What is true about the slope of the function below y = 4x + 3

Karo-lina-s [1.5K]

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$\blue{\textsf{\textbf{\underline{\underline{Question:-}}}}}$

Which is true about the slope of the function y=4x+3?

$\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}$

The slope of the function y=4x+3 is 4; in equations like this one, the slope is simply the number before x.

The rise is 4, and the run is 1.

Remember, slope is also defined as "Rise/Run"

[Note:- You haven't listed any options here, could you kindly add them in the comments?]

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4 0

2 years ago

PLEASE HELP NOW

slavikrds [6]

Answer:

Solution=96°+x+35°

=x+96°+35°

=x=96°-35°

=x=61°

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PIT_PIT [208]

It would be: 5/45 = 1/9 = 10/90 = 15/135
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