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3 years ago

Find the tenth term in the sequence

Mathematics

1 answer:

attashe74 [19]3 years ago

4 0

Answer: The tenth term in the sequence is 512.

Step-by-step explanation:

Since we have given that

$a_n=2^{n-1}$

We need to find the tenth term:

It means n = 10

So, it becomes

$a_{10}=2^{10-1}\\\\a_{10}=2^9\\\\a_{10}=2\times 2\times 2\times 2\times 2\times 2\times 2\times 2\times 2\\\\a_{10}=512$

Hence, the tenth term in the sequence is 512.

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Given the area of a square is 225 ft.² what is the length of each side

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Answer:

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Step-by-step explanation:

the square root of 225 is 15, so the answer is 15ft

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Answer:

The temperature of metal after five years = -18.96875

Step-by-step explanation:

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2 years ago

Find the equation of the tangent of x^2- xy + y^2 =7 at (-1, 2)

Citrus2011 [14]

Answer:

It is 3y = 4x + 10

Step-by-step explanation:

Let's first get the slope of the curve.

[ slope is the derivative of the equation ]

${x}^{2} - xy + {y}^{2} = 7$

introduce dy/dx :

$\frac{d}{dx} ( {x}^{2} - xy + {y}^{2} ) = \frac{d}{dx} (7) \\ \\ 2x - (y + \frac{dy}{dx} ) + 2y \frac{dy}{dx} = 0$

make dy/dx the subject:

$2x - y - \frac{dy}{dx} + 2y \frac{dy}{dx} = 0 \\ \\ 2y \frac{dy}{dx} - \frac{dy}{dx} = y - 2x \\ \\ \frac{dy}{dx} (2y - 1) = y - 2x \\ \\ \frac{dy}{dx} = \frac{y - 2x}{2y - 1}$

At point (-1, 2):

$\frac{dy}{dx} = \frac{2 - 2( - 1)}{2(2) - 1} \\ \\ slope = \frac{4}{3}$

but a tangent has the same slope as the curve:

$y = mx + c$

m is the slope

c is the y-intercept

At (-1, 2):

$2 = ( - 1 \times \frac{4}{3} ) + c \\ \\ c = 2 + \frac{4}{3} \\ \\ c = \frac{10}{3}$

equation:

$y = \frac{4}{3} x + \frac{10}{3} \\ \\ { \boxed{3y = 4x + 10}}$

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