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Marina86 [1]
3 years ago
13

Which of the following correctly uses absolute value to show the distance between −50 and 12? |−50 − 12| = |−62| = −62 units

Mathematics
2 answers:
Tanya [424]3 years ago
6 0
C,
The third one. Hope my answer helped you
torisob [31]3 years ago
3 0

Answer:

C. 62 units

Step-by-step explanation:

The absolute value of a number A is the positive distance between 0 and the number A (you can think this distance as the distance measured with a ruler from 0 to the number). For example:

|-2|=2 ,  |25|=25,  |-3|=3, |-25.3|=25.3

Note that the absolte value is always positive.

The distance between two numbers P,Q in the real line is the absolute value of the difference between the two points:

d=|P-Q|

Hence, the distnce between P=-50 and Q=12 is equal to

d=|P-Q|=|-50-12|=|-62|=62.

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6. Evaluate the following expression: 10 + 4(6-2)<br> А. 56<br> B. 82<br> С. 18<br> D. 26
irakobra [83]

Answer:

D. 26

Step-by-step explanation:

10+4(6-2)\\10+4(4)\\10+16\\26

7 0
2 years ago
Read 2 more answers
hus, D satisfying ​(ABC)DequalsI exists. Why does the expression for D found above also satisfy ​D(ABC)equalsI​, thereby showing
Assoli18 [71]

Complete Question

The complete question is shown on the first uploaded image

Answer:

First Question

Option A is correct

Second  Question

Option C is correct

Third   Question

     D =  A^{-1}  *  B^{-1} *  C^{-1}

Fourth   Question

  So substituting for D in  (ABC) D =  I

                 (ABC) *  A^{-1}  *  B^{-1} *  C^{-1} =  I

                 I =  I

This proof that  ABC is invertible

Step-by-step explanation:

From the question we are told that

   A , B and  C are invertible which means that A^{-1} , B^{-1}, C^{-1} exist

Now

 From the question

          (ABC) D =  I

Where I is an identity matrix

   Now when we multiply both sides by  A^{-1}  we have

          A^{-1}  A BCD =  A^{-1} * I

          IBCD =  A^{-1}

Now when we multiply both sides by  B^{-1}  we have  

         B^{-1 } *I BCD =  A^{-1}  *  B^{-1}

         I CD =  A^{-1}  *  B^{-1}

Now when we multiply both sides by  C^{-1}  we have  

          C^{-1} * I CD =  A^{-1}  *  B^{-1} *  C^{-1}

              I D =  A^{-1}  *  B^{-1} *  C^{-1}

                 D =  A^{-1}  *  B^{-1} *  C^{-1}

So substituting for D in the above equation

                 (ABC) *  A^{-1}  *  B^{-1} *  C^{-1} =  I

                 I =  I

This proof that  ABC is invertible

 

4 0
3 years ago
Please help ♥ 10 points and brainliest to first and best answer ;)
hram777 [196]

Answer:

the answer is i think is 60.7

7 0
3 years ago
Read 2 more answers
-4/7 + 2/7x - 14x + 4/7
alexgriva [62]

Answer:

The solved given expression is

\frac{-4}{7}+\frac{2}{7}x-14x+\frac{4}{7}=\frac{-96x}{7}

Step-by-step explanation:

Given expression is \frac{-4}{7}+\frac{2}{7}x-14x+\frac{4}{7}

To solve the given expression :

\frac{-4}{7}+\frac{2}{7}x-14x+\frac{4}{7}

=\frac{-4+4+2x}{7}-14x

=\frac{0+2x}{7}-14x

=\frac{2x}{7}-14x

=\frac{2x-14x(7)}{7}

=\frac{2x-98x}{7}

=\frac{-96x}{7}

Therefore \frac{-4}{7}+\frac{2}{7}x-14x+\frac{4}{7}=\frac{-96x}{7}

Therefore the solved given expression is

\frac{-4}{7}+\frac{2}{7}x-14x+\frac{4}{7}=\frac{-96x}{7}

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3 years ago
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See the picture attached
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