All categories

3 years ago

(will mark brainliest ) Which of the following best describes the expression 5(x + 2)? (5 points)

Mathematics

1 answer:

Lunna [17]3 years ago

8 0

Answer:

Step-by-step explanation:

The only one of these possible answers that could be correct is the fourth one:

The product of a constant factor 5 and a 2-term factor x + 2. That '5' in front of (x+2) multiplies (x+2), and so the result is a product.

You might be interested in

which number is a prime factor of 210 A.2 to the 6th power B.6 to the 2nd power or 6 squared C.12 to the 6th power.Exponents and

Elden [556K]

210=2*3*5*7
none of them

if you meant 2¹⁰ then the answer is A because 2¹⁰=2*2*2*2*2*2*2*2*2*2=(2⁶)(2⁴)

A

8 0

3 years ago

I’ll give brainliest please help asap :D

USPshnik [31]

<h3>Answer:</h3><h3> C</h3><h3 /><h3>Step-by-step explanation:</h3><h3>It is C.</h3>

Thanks!

Hope i helped

4 0

2 years ago

In a recent year 33.2% of all registered doctors are female. If there were 56,400 female register doctors that year, what was th

bixtya [17]

56400 ÷ 0.332
<span>169879 total people
</span>
Hope this helps!

4 0

3 years ago

How to find the length of a cylinder when given the volume and radius?

andriy [413]

It’s the heigh. Times the radius and volume

h= V/r

6 0

3 years ago

Read 2 more answers

(1 point) Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference betw

slavikrds [6]

Answer:

a. $\frac{dT}{dt}=k(T-Tm); T(0)=190$

b. $C_{0}=122$

c. $k=-0.00259$

d. $t=153.39838\\$ minutos

Step-by-step explanation:

a. Newton's law of cooling states that the speed with which a body is cooled is proportional to the difference between its temperature and that of the medium in which it is found. Then, the initial value problem is given by:

$Tm=68$

$\frac{dT}{dt}=k(T-Tm); T(0)=190$

b. The differential equation obtained is a differential equation of separable variables:

$\frac{dT}{T-Tm}=kdt\\\\\int {\frac{dT}{T-Tm}}=\int{kdt}\\\\Ln|T-Tm|=kt+C\\\\T(t)=C_{0}e^{kt}+Tm=C_{0}e^{kt}+68\\\\T(0)=C_{0}e^{k(0)}+68=190\\\\C_{0}=122$

c. After 33 minutes of serving the coffee has cooled to 180°:

$T(33)=122e^{33k}+68=180\\\\e^{33k}=\frac{112}{122}\\\\33k=Ln(\frac{112}{122})\\\\k=-0.00259$

$150=122e^{-0.00259t}+68\\\\Ln(\frac{150-68}{122})=-0.00259t\\\\t=153.39838\\\\$

8 0

3 years ago