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3 years ago

13

Which is the graph of y=[x]-2?

1 answer:

Korolek [52]3 years ago

7 0

Answer: C is the answer to this problem I believe

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The use of mathematical methods to study the spread of contagious diseases goes back at least to some work by Daniel Bernoulli i

harina [27]

Answer:

a

$y(t) = y_o e^{\beta t}$

b

$x(t) = x_o e^{\frac{-\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

c

$\lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }$

Step-by-step explanation:

From the question we are told that

$\frac{dy}{y} = -\beta dt$

Now integrating both sides

$ln y = \beta t + c$

Now taking the exponent of both sides

$y(t) = e^{\beta t + c}$

=> $y(t) = e^{\beta t} e^c$

Let $e^c = C$

So

$y(t) = C e^{\beta t}$

Now from the question we are told that

$y(0) = y_o$

Hence

$y(0) = y_o = Ce^{\beta * 0}$

=> $y_o = C$

So

$y(t) = y_o e^{\beta t}$

From the question we are told that

$\frac{dx}{dt} = -\alpha xy$

substituting for y

$\frac{dx}{dt} = - \alpha x(y_o e^{-\beta t })$

=> $\frac{dx}{x} = -\alpha y_oe^{-\beta t} dt$

Now integrating both sides

$lnx = \alpha \frac{y_o}{\beta } e^{-\beta t} + c$

Now taking the exponent of both sides

$x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} + c}$

=> $x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} } e^c$

Let $e^c = A$

=> $x(t) =K e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }$

Now from the question we are told that

$x(0) = x_o$

So

$x(0)=x_o =K e^{\alpha \frac{y_o}{\beta } e^{-\beta * 0} }$

=> $x_o = K e^{\frac {\alpha y_o }{\beta } }$

divide both side by $(K * x_o)$

=> $K = x_o e^{\frac {\alpha y_o }{\beta } }$

So

$x(t) =x_o e^{\frac {-\alpha y_o }{\beta } } * e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }$

=> $x(t)= x_o e^{\frac{-\alpha * y_o }{\beta} + \frac{\alpha y_o}{\beta } e^{-\beta t} }$

=> $x(t) = x_o e^{\frac{\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

Generally as t tends to infinity , $e^{- \beta t}$ tends to zero

so

$\lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }$

5 0

3 years ago

A recipe for bran muffins calls for 2 1/2 cups of bran flakes. The recipe yields 9 muffins. How much bran flakes should be used

kolbaska11 [484]

10/3 bran flakes can make a dozen muffins

A recipe requires 2 1/2 cups of bran flakes

The recipe can make 9 muffins

Let's calculate the amount of bran flakes it will take to make 1 muffin

5/2 = 9

x= 1

cross multiply

9x= 5/2

x= 5/18

A dozen is 12, the number of bran flakes to make a dozen can be calculated as follows

5/18= 1

y= 12

cross multiply

y= 5/18 × 12

y= 10/3

Hence it will take 10/3 to make a dozen muffins

Read more here

brainly.com/question/13876035?referrer=searchResults

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4 0

1 year ago

14,219.92 The 9 in the ones place is _______ the value of the 9 in the tenths place.

Elza [17]

Answer:

less

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

NEED HELP ASAP (ILL GIVE BRAINLIST)

strojnjashka [21]

Answer:

the answer is 33 9/11

Step-by-step explanation:

multiply the fractions

.

.

7 0

2 years ago

Read 2 more answers

joshua is 6 years younger than kerryn. Kerryn age can be represented by x.write an expression representing joshua's age.

never [62]

Answer: X - 6

If you were to write an equation you can use Y to represent Joshua's age, X - 6 = Y

3 0

3 years ago