Answer:
The ratio of boys to girls to 5:7
Let the number of boys be 5x
Let the number of girls be 7x
5x = 30
x = 6
Now just plug in 6 for the x in 7x
and number of girls 7 x 6 = 42
Answer:
ti is m(B{AC=70*
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
3x−5=
1
2
x+2x
3x+−5=
1
2
x+2x
3x−5=(
1
2
x+2x)(Combine Like Terms)
3x−5=
5
2
x
3x−5=
5
2
x
Step 2: Subtract 5/2x from both sides.
3x−5−
5
2
x=
5
2
x−
5
2
x
1
2
x−5=0
Step 3: Add 5 to both sides.
1
2
x−5+5=0+5
1
2
x=5
Step 4: Multiply both sides by 2.
2*(
1
2
x)=(2)*(5)
x=10
So, we know that it takes Sam 1 mph up and 9 mph down and it takes Liam both 2 mph down and up the hill. So if we divide the 2 mph for Liam by 2 miles (the whole length of the hill) we will get 1 or 1 hour. Then we do 1/1 (i don't know how to explain this part of why we do that, sorry) and than we do 1 / 9 and we get 1/9 so we add them and get 1 1/9 so that's Sam's time.
So, Liam took one hour and Sam took 1 and 1/9 hours, in conclusion liam was faster
<h2> (I'm really sorry for my bad explaining, i tried my best)</h2>
Answer:
The nth term of an AP will be 27 -7n.
Step-by-step explanation:
First five terms of the Arthemetic Sequence is given to us , which is 26 , 19 , 12 , 5
Hence here Common Difference can be found by subtracting two consecutive terms . Here which is 19 - 26 = (-7) .
Here first term is 26 .
And the nth term of an AP is given by ,
★ T_n = a + ( n - 1) d
<u>Subst</u><u>ituting</u><u> respective</u><u> values</u><u> </u><u>,</u>
⇒ T_n = a + ( n - 1 )d
⇒ T_n = 26 + (n - 1)(-7)
⇒ T_n = 26 -7n+1
⇒ T_n = 27 - 7n
<h3>
<u>Hence </u><u>the</u><u> </u><u>nth</u><u> </u><u>term</u><u> of</u><u> an</u><u> </u><u>AP</u><u> </u><u>can</u><u> </u><u>be</u><u> </u><u>found </u><u>using </u><u>T_</u><u>n</u><u> </u><u>=</u><u> </u><u>2</u><u>7</u><u> </u><u>-</u><u> </u><u>7</u><u>n</u><u>. </u></h3>