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3 years ago

6

You run around the perimeter of the baseball field at a rate of 8 feet/ second how long does it take you to run around the baseb

all field

1 answer:

Anna35 [415]3 years ago

5 0

11.25 seconds, if it takes you 1 second to run 8 feet. This is not realistic.

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What is the answer to the problem <br><br><img src="https://tex.z-dn.net/?f=%28x%20%7B3%7D%29%5E%7B3%7D%20%3D%20x%5En" id="TexFo

11Alexandr11 [23.1K]

Solve for x:
x^9 = n x

Subtract n x from both sides:
x^9 - n x = 0

Factor x and constant terms from the left hand side:
-x (n - x^8) = 0

Multiply both sides by -1:
x (n - x^8) = 0

Split into two equations:
x = 0 or n - x^8 = 0

Subtract n from both sides:
x = 0 or -x^8 = -n

Multiply both sides by -1:
x = 0 or x^8 = n

Taking 8^th roots gives n^(1/8) times the 8^th roots of unity:
Answer: x = 0 or x = -n^(1/8) or x = -i n^(1/8) or x = i n^(1/8) or x = n^(1/8) or x = -(-1)^(1/4) n^(1/8) or x = (-1)^(1/4) n^(1/8) or x = -(-1)^(3/4) n^(1/8) or x = (-1)^(3/4) n^(1/8)

3 0

3 years ago

△QRS is rotated about point P to △Q′R′S′ .

Sedbober [7]

Answer:

As Given △QRS is rotated about point P to △Q′R′S′ .

As we know after rotation by any angle of pre-image neither the shape nor size of the image changes, the image after rotation is congruent to pre image.

Out of the options given

→The corresponding lengths, from the point of rotation, between the pre-image and the image are preserved.

→The corresponding angle measurements in each triangle between the pre-image and the image are preserved.

are true.

4 0

3 years ago

Use any method to multiply (3a + 2b - c)(a - b + 2c).

Alla [95]

Answer: $3a^{2}-ab + 5ac- 2b^{2} + 5bc-2c^{2}$

Step-by-step explanation:

(3a + 2b − c) (a − b + 2c)

Expand (3a + 2b − c) (a − b + 2c) by multiplying each term in the first expression by each term in the second expression.

3a ⋅ a + 3a (−b) + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

3 (a ⋅ a) + 3a (−b) + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

3a^2 + 3a (−b) + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 + 3 ⋅ −1ab + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 3 ⋅ 2ac + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 6ac + 2ba + 2 ⋅ −1b ⋅ b + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba + 2 ⋅ −1 (b ⋅ b) + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba + 2 ⋅ −1b^2 + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 2b (2c) − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 2 ⋅ 2bc − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca − 1 ⋅ −1cb − c (2c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + 1cb − c (2c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 1 ⋅ 2c ⋅ c

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 1 ⋅ 2 (c ⋅ c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 1 ⋅ 2c^2

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 2c^2

3a^2 − 3ab + 2ab + 6ac − 2b^2 + 4bc − ca + cb − 2c^2

3a^2 − ab + 6ac − 2b^2 + 4bc − ca + cb − 2c^2

3a^2 − ab − 2b^2 + 4bc + 6ac − 1ac + cb − 2c^2

3a^2 − ab − 2b^2 + 4bc + 5ac + cb − 2c^2

3a^2 − ab − 2b^2 + 4bc + bc + 5ac − 2c^2

3a^2 − ab − 2b^2 + 5bc + 5ac − 2c^2

3a^2 − ab − 2b^2 + 5ac + 5bc − 2c^2

3a^2 − ab + 5ac − 2b^2 + 5bc − 2c^2

6 0

3 years ago

Angle e measures 126LaTeX: ^\circ∘. What is the measure of LaTeX: \angle∠h?

SVEN [57.7K]

Answer:

$m\angle h=126^o$

Step-by-step explanation:

we know hat

<u><em>Vertical Angles</em></u> are the angles opposite each other when two lines cross. They are always congruent.

In this problem

$m\angle h=m\angle e$ ----> by vertical angles

we have

$m\angle e=126^o$ ---> given problem

therefore

$m\angle h=126^o$

3 0

3 years ago

Can I have some help please.

Virty [35]

Answer:

I cant really see its up side down if you can do it again the right way then I tell you what it is but its kinda hard to see the way im seeing it

8 0

3 years ago