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The present age of Jane is 45 years old and present age of her sister is 9 years old
<em><u>Solution:</u></em>
Let the present age of Jane be "x"
Let the present age of her sister be "y"
<em><u>Jane is 5 times older than her sister</u></em>
present age of Jane = 5(present age of her sister)
x = 5y ---------- eqn 1
<em><u>In 3 years, Jane’s sister will be 1/4 her age</u></em>
Age of sister after 3 years = 3 + y
Age of jane after 3 years = 3 + x
Age of sister after 3 years = 1/4(age of jane after 3 years)

Substitute eqn 1 in above equation

Substitute y = 9 in eqn 1
x = 5(9)
x = 45
Thus present age of Jane is 45 years old and present age of her sister is 9 years old
Answer: dimond
Step-by-step explanation:
Answer:
23, 25, 27
Step-by-step explanation:
It can be convenient to work "consecutive integer" problems by using a variable to represent the middle one.
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<h3>setup</h3>
Let x represent the middle integer. Then (x-2) is the first of the three odd integers, and (x+2) is the third. The given relation is ...
2(x -2) +3x = 67 +2(x +2)
<h3>solution</h3>
5x -4 = 2x +71 . . . . . simplify
3x = 75 . . . . . . . . add 4-2x
x = 25 . . . . . . . divide by 3
The three integers are 23, 25, 27.
Answer:
violates the rules or bedmas
Step-by-step explanation:
When doing questions like these, bedmas comes into play. althought multiplication and division are the same in terms of priority, you should do the one that comes first when reading the equation/formula left to right.
this would mean you would do 2 ÷ 3 and the answer would be multiplied by 12.