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Shalnov [3]
3 years ago
12

What is the value of x? Enter your answer, as a decimal, in the box.

Mathematics
1 answer:
svlad2 [7]3 years ago
7 0
Im not sure about this one but i think x is 60 since the line Ed basically bisects the angle E which also bisects the line GH in half so that 62=x+2 and then solve for the equation 
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A line passes through tge points (1,-3) and (4,6) what is the zero of this line ?
Maru [420]

Answer:

<em>The zero of the line is (2,0)</em>

Step-by-step explanation:

The equation of a line passing through points (x1,y1) and (x2,y2) can be found as:

\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

We are given the points (1,-3) and (4,6). Substituting:

\displaystyle y+3=\frac{6+3}{4-1}(x-1)

Operating:

\displaystyle y+3=\frac{9}{3}(x-1)

y+3=3(x-1)

The zero of this line can be found by making y=0 and solving for x:

0+3=3(x-1)

3=3x-3

Adding 3:

6=3x

Solving:

x = 2

The zero of the line is (2,0)

3 0
2 years ago
A carpet is in the shape of a rectangle 6 metres by 4 metres. Mel wants to put tape all around the edges of the carpet. Work out
Oxana [17]
Perimeter = length + length + width + width
6 + 6 + 4 + 4 = 20 metres
5 0
3 years ago
When the points are in the SAME quadrant, what operation do you do to find the distance between them?
Mademuasel [1]
Use this formula, it’s called distance formula

8 0
2 years ago
Please help because no one been answering my questions
never [62]

Answer:

BC = 8 \sqrt{2}

Step-by-step explanation:

\sin(45)  =  \frac{opposite}{hypotenuse}

\sin(45)  =  \frac{8}{BC}

(BC) \sin(45)  =  \frac{8}{x} (BC)

(BC) \sin(45)  = 8

\frac{(BC) \sin(45) }{ \sin(45) }  =  \frac{8}{ \sin(45) }

BC =  \frac{8}{ \sin(45) }

BC = 8 \sqrt{2}

5 0
2 years ago
The formula c = 5p + 210 relates c, the total cost in dollars of hosting a birthday party at a skating rink, to
Lesechka [4]
It would be 31 because if they are willing to spend 365 on the party then you’d replace the c with 365 and then subtract 210 from 365 and then divide 5 to get the variable by itself
5 0
3 years ago
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