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svlad2 [7]
3 years ago
10

In an automobile factory, a component requires 0.75 hours of labor per unit in Work Center A and 1 hour of setup time. The plann

ed order release (order size) for a week is 200 units. What is the capacity requirement for a week at Work Center A
Business
1 answer:
lesantik [10]3 years ago
7 0

The capacity requirement for a week at Work Center A is 151 hours

Explanation:

Labor hours per unit of component in automobile factory = 0.75 hours

Setup time required in Work Center A = 1 hour

The planned order size for a week = 200 units.

Capacity = Setup time + [Processing time × Order size].

  • Capacity = 1 + (0.75 * 200)
  • Capacity = 1 + 150
  • Capacity = 151 hours

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Answer:

c. paying lower prices to its suppliers.

Explanation:

A : clearance of discontinued inventory.  

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B : selling products with a lower markup.

Markups are the ratio of gross profit to sales price.

D : increased competition resulting in a lower selling price.

lower prices will lead to higher sales volumes, which may make up for the lower profit margin

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3 years ago
Tony's marginal income tax rate is 24%, and he pays FICA tax on his entire salary (7.65%). Tony's employer offered him a choice
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Answer: The fringe benefit is worth $182 more than the additional salary.

Explanation:

The Fringe benefit is valued at $3,600.

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= 5,000 - (5,000 * 24%) - (5,000 * 7.65%)

= 5,000 - 1,200 - 382.5

= $3,418

The Fringe benefit is worth more than the salary by:

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8 0
3 years ago
Slow​ 'n Steady,​ Inc., has a stock price of $ 34​, will pay a dividend next year of $ 3.10​, and has expected dividend growth o
erica [24]

Answer:

10.92%

Explanation:

The formula and the computation of the estimated cost of equity capital is shown below:

Stock price = Next year dividend ÷ (cost of equity - expected dividend growth rate)

We assume the cost of equity be X

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3 years ago
A small market orders copies of a certain magazine for its magazine rack each week. Let X 5 demand for the magazine, with pmf Su
Oksanka [162]

Answer:

See explanation below.

Explanation:

Let X the random variable that represent the demand for the magazine, the pmf for X is given by:

X       1            2           3          4        5        6      

P(X)  1/15      2/15       3/15     4/15   3/15     2/15

3 magazines

For this case the total spent is 2*3 = $ 6

And the net revenue for this case would be:

$4-$6 = -$2 , X=1 (demand 1)

$4*2-$6 = $2 , X=2 (demand 2)

$4*3-$6 = $6 , X=3 (demand 3)

For the values of X=4,5,6 the net revenue will be $6 since the number of magazines is 3

And the expected value for the net revenue would be:

E(R) = \frac{1}{15} *(-2) +\frac{2}{15} *(2) +\frac{3}{15}*(6) + \frac{4}{15}*(6) +\frac{3}{15}*(6) +\frac{2}{15}*(6) = \frac{74}{15}=4.93

4 magazines

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And the net revenue for this case would be:

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$4*2-$8 = $0 , X=2 (demand 2)

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$4*4-$8 = $8 , X=4 (demand 4)

For the values of X=5,6 the net revenue will be $8 since the number of magazines is 4

And the expected value for the net revenue would be:

E(R) = \frac{1}{15} *(-4) +\frac{2}{15} *(0) +\frac{3}{15}*(4) + \frac{4}{15}*(8) +\frac{3}{15}*(8) +\frac{2}{15}*(8) = \frac{80}{15}=5.33

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