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Rzqust [24]
3 years ago
7

The equation of a circle is ​x2+4x+y2−10y+13=0​ .

Mathematics
2 answers:
kiruha [24]3 years ago
8 0
X^2+4x+4+y^2-10y+25=-13+25+4

(x+2)^2 + (y-5)^2= 16
Third option
Afina-wow [57]3 years ago
6 0

Answer:

(x+2)^2+(y-5)^2=16

Step-by-step explanation:

Given : x^2+4x+y^2-10y+13=0

To Find: What is the equation of the circle in standard form?

Solution:

x^2+4x+y^2-10y+13=0

x^2+4x+2^2-2^2+y^2-10y+5^2-5^2+13=0

(x+2)^2-4+(y-5)^2-25+13=0

(x+2)^2+(y-5)^2-29+13=0

(x+2)^2+(y-5)^2-16=0

(x+2)^2+(y-5)^2=16

Hence the equation of the circle in standard form is (x+2)^2+(y-5)^2=16

So, Option C is correct.

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