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Lady_Fox [76]
4 years ago
11

Bar graphs, line graphs, tables, and charts are all ways that scientists ____________________ data.

Chemistry
2 answers:
Alexandra [31]4 years ago
8 0

Answer:organize

Explanation:

All scientists organize data using these things

svetoff [14.1K]4 years ago
4 0

Answer: oraganize

Explanation: hope that helps you

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O que são processos físicos de separação das misturas? Dê 3 exemplos
chubhunter [2.5K]

Answer:

Explanation:

The physical methods of separating mixtures are used in sorting a mixture of substances.

It requires no chemical changes occurring between their components and parts in any significant way.

Examples are:

  1. Decantation
  2. Filtration
  3. Sublimation
  4. Magnetism
  5. Centrifugation

The methods simply relies on the physical properties of matter.

8 0
4 years ago
What kind of molecule is glucose
Scrat [10]
Organic molecule. In particular,  a carbohydrate.
6 0
3 years ago
Given the reaction at equilibrium:
VLD [36.1K]

Answer:

decrease

Explanation:

because the equilibrium will shift to  right side

8 0
3 years ago
What happens to a person's weight on smaller and larger planets?
wlad13 [49]

Answer:

The amount of gravity they have depends on their size. So, a small planet has less and a larger planet has more gravity. Just like the planets, a person with more mass has more gravity and therefore weighs more.

5 0
4 years ago
Calculate the frequency of the light emitted by ahydrogen atom
lesya [120]

Answer:  0.31\times 10^{16}Hz.

Explanation:

E=\frac{hc}{\lambda}

\lambda = Wavelength of radiation

E= energy

Using Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )\times Z^2

Where,

\lambda = Wavelength of radiation  = ?

R_H = Rydberg's Constant

n_f = Higher energy level = 4

n_i= Lower energy level = 1

Z= atomic number = 1 (for hydrogen)

Putting the values, in above equation, we get

\frac{1}{\lambda}=10973731.6m^{-1}\left(\frac{1}{1^2}-\frac{1}{4^2} \right )\times 1

\lambda=9.7\times 10^{-8}m

The relationship between wavelength and frequency of the wave follows the equation:

\nu=\frac{c}{\lambda}

where,

\nu = frequency of the wave  = ?

c = speed of light  = 3\times 10^8ms^{-1}

\lambda = wavelength of the wave = 9.7\times 10^{-8}m

\nu=\frac{3\times 10^8ms^{-1}}{9.7\times 10^{-8}m}

\nu=0.31\times 10^{16}s^{-1}=0.31\times 10^{16}Hz

The frequency of the light emitted by a hydrogen atom  during a transition of its electron from the n = 4 to the n = 1  principal energy level is 0.31\times 10^{16}Hz.

5 0
3 years ago
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