Answer:
D) 373 mm Hg.
Explanation:
We can solve this problem by keeping in mind<em> Dalton's law of partial pressures</em>, which states that the total pressure of a mixture of gases is equal to the sum of each gas' partial pressures. In other words, for this case:
- Total Pressure = Ne Pressure + CO₂ Pressure + O₂ Pressure + H₂ Pressure
- 1245 mm Hg = Ne Pressure + 145 mm Hg + 228 mm Hg + 499 mm Hg
The answer is option D) 373 mm Hg.
Answer:
The density of the crystal is 10.22 g/cm³
Explanation:
Step 1: Data given
Molybdenum (Mo) has a BCC crystal structure
atomic radius = 0.1363 nm
atomic weight of 95.94 g/mol
Step 2: Calculate density of a bcc crystal
Density ρ= (nA
*Mo)/(Vc*Na)
⇒For BCC, n = 2 atoms/unit cell, and realizing that V
c = a
³
a = 4R/√3
Vc =(4R/√3)³
AMo = atomic weight = 95.94 g/mol
ρ = (n*A
Mo)/((4R/√3)³ *Na)
⇒with n = 2 atoms/unit cell
⇒ with AMo = 95.94 g/mol
⇒ with Vc =(4R/√3)³ = (4*0.1363*10-7 cm)³ /(√3)³
⇒with Na = 6.022*10^23 atoms/mol
ρ =10.22 g/cm³
The density of the crystal is 10.22 g/cm³
Answer:
no reaction
Explanation:
becaus aluminum is very reactive than zinc
Answer:
a. KCl, c. BaCl2 and e. LiF.
Explanation:
Hello,
In this case, we can identify the ionic compounds by verifying the difference in the electronegativity between the bonding compounds when it is 1.7 or more (otherwise it is covalent) as shown below:
a. KCl: 3.0-0.9=2.1 -> Ionic.
b. C2H4: 2.5-2.1=0.4 -> Covalent.
c. BaCl2: 3.0-0.8=2.2 -> Ionic.
d. SiCl4: 3.0-1.8=1.2 -> Covalent.
e. LiF: 4.0-1.0=3.0 -> Ionic.
Therefore, ionic compounds are a. KCl, c. BaCl2 and e. LiF.
Regards.
