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fiasKO [112]
3 years ago
6

Which factors affect electronegativity?

Chemistry
2 answers:
Vitek1552 [10]3 years ago
7 0
I think it’s C atomic radius and numbers of unshielded protons
11111nata11111 [884]3 years ago
4 0

Answer:

I guess it would be C.

Explanation:

because it sounds familiar

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it takes 151 kJ/mol to break an iodine-iodine single bond. calculate the maximum wavelength of light for which an iodine-iodine
Allisa [31]

Answer:

The wavelength of light require to brake an single I-I bond is  7.92 × 10⁻⁷ m

Explanation:

Amount of energy required to break the one mole of iodine-iodine single bond = 151 KJ

amount of energy to break one iodine -iodine bond = (151 KJ/mol )/ 6.02 × 10²³/mol = 2.51 × 10⁻²² KJ

or

2.51 × 10⁻¹⁹ J

Formula:

E = hc / λ    

h = planck's constant    = 6.626 × 10⁻³⁴ js

c = speed of light = 3 × 10⁸ m/s

λ = wavelength

Solution:

E = hc / λ  

λ   = hc / E

λ   =  (6.626 × 10⁻³⁴ js × 3 × 10⁸ m/s ) / 2.51 × 10⁻¹⁹ J

λ   = 19.878 × 10⁻²⁶ j .m / 2.51 × 10⁻¹⁹ J

λ   = 7.92 × 10⁻⁷ m

6 0
3 years ago
A chemist mixes 75.0 g of an unknown substance at 96.5°C with 1,150 g of water at 25.0°C. If the final temperature of the system
AleksAgata [21]
To do this problem it is necessary to take into account that the heat given by the unknown substance is equal to the heat absorbed by the water, but considering the correct sign:

-m\cdot c_e\cdot \Delta T = m_w\cdot c_e_w\cdot \Delta T_w

Clearing the specific heat of the unknown substance:

c_e = \frac{m_w\cdot c_e_w\cdot \Delta T_w}{m\cdot \Delta T} = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot (37.1 - 25.0)^\circ C}{75\ g\cdot (37.1 - 96.5)^\circ C}

c_e = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot 12.1^\circ C}{75\ g\cdot (-59.4)^\circ C} = \bf 13.07\frac{J}{g\cdot ^\circ C}
6 0
3 years ago
A helium balloon at 23 C has a volume of 755 mL. The balloon is placed into a freezer kept at -10 C. Assuming pressure is consta
Vera_Pavlovna [14]

Explanation:

T1/V1 = T2/V2

V2 = T2 x V1/T1

V2 = 296.15x535/319.15

V2 = 496.44mL

5 0
3 years ago
When 7.02 grams of a compound containing only carbon and hydrogen was burned completely in 25.5 grams of oxygen, 21.0 grams of c
seropon [69]

Mass of water is 11.52 grams.

Overall chemical equation for reaction of combustion a compound containing only carbon and hydrogen:

CxHy + O₂ → xCO₂ + y/2H₂O

m(CxHy) = 7.02 g; mass of the compound

m(O₂) = 25.5 g; mass of oxygen

m(CO₂) = 21.0 g; mass of carbon dioxide

m(H₂O) = ?; mass of water

Conservation of matter states that the mass of the reactants have to be equal to the mass of the products.

m(CxHy) + m(O₂) = m(CO₂) + m(H₂O)

7.02 g + 25.5 g = 21.0 g + m(H₂O)

m(H₂O) = 32.52 g - 21.0 g

m(H₂O) = 11.52 g; mass of water

More about conservation of matter: brainly.com/question/18318085

#SPJ4

6 0
2 years ago
How many moles of NaCl are equivalent to 15.6<br> grams of NaCl
NeX [460]

One mole of NaCl has a mass of approximately 58.5 grams. This gives it a conversion factor of 1/58.5

Hope This Helped

4 0
4 years ago
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