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3 years ago

Given the reaction at equilibrium:

Chemistry

1 answer:

VLD [36.1K]3 years ago

8 0

Answer:

decrease

Explanation:

because the equilibrium will shift to right side

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If a frog initially contained 2 grams of carbon-14 and the half-life of carbon-14 is 5,730 years, how much carbon-14 remains in

andreyandreev [35.5K]

Half life is the time taken for a radioactive isotope to decay by half its original mass. In this case the half life of carbon-14 is 5.730 years.
Using the formula;
New mass = original mass × (1/2)^n; where n is the number of half lives (in this case n=1 )
New mass = 2 g × (1/2)^1
= 1 g
Therefore; the mass of carbon-14 that remains will be 1 g

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3 years ago

A chemical engineer is studying the two reactions shown in the table below.

Kamila [148]

Explanation:

Here are the answers. Do note that I had to convert the enthalpy to joules and temperature to Kelvin to make the unit for entropy work out.

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3 years ago

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Brilliant_brown [7]

Answer:

Iconic bond or covalent bond

Explanation:

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2 years ago

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Both carbon dioxide and water are molecules containing three atoms. Explain, in terms of structure, why water is polar, but carb

ANTONII [103]

I do not know the answer because yes

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2 years ago

How many moles are in 7.00E24 atoms of Ca?

iris [78.8K]

Explanation:

In chemistry, a mole is the base unit of the amount of substance in a system containing elementary entities (atoms, molecules, ions, electrons), and one mole of substance corresponds to the Avogadro's constant or $6.023 \ \times \ 10^{23}$ entities. The stoichiometry equation that relates the amount of substance into the measurement in moles is

$n \ = \ \displaystyle\frac{\alpha}{N_{A}}$ ,

where $n$ is the number of moles, $\alpha$ is the amount of substance and $N_{A}$ is the Avogadro's constant.

Therefore,

$n \ = \ \displaystyle\frac{7.00 \ \times \ 10^{24} \ \text{atoms}}{6.023 \ \times \ 10^{23} \ \text{atoms mol}^{-1}} \\ \\ n \ = \ 11.624 \ \text{mol}$ .

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2 years ago