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Talja [164]
3 years ago
12

Celeste is writing a paper. However, two pages in, her computer shuts down unexpectedly. She never saved her paper, and all her

work is lost. What kind of memory was the computer using while Celeste was typing her paper?
A.Secondary memory
B.Read-only memory (ROM)
C.Microprocessor
D.Random access memory (RAM)
Computers and Technology
2 answers:
alekssr [168]3 years ago
8 0
<span>Random access memory (RAM)</span>
PolarNik [594]3 years ago
3 0

D is right for apex Learners!

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Answer:

(a)\ 222_{10} = DE_{16} --- True

(b)\ D7_{16} = 11010011_2 --- False

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Explanation:

Required

Determine if the statements are true or not.

(a)\ 222_{10} = DE_{16}

To do this, we convert DE from base 16 to base 10 using product rule.

So, we have:

DE_{16} = D * 16^1 + E * 16^0

In hexadecimal.

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So, we have:

DE_{16} = 13 * 16^1 + 14 * 16^0

DE_{16} = 222_{10}

Hence:

(a) is true

(b)\ D7_{16} = 11010011_2

First, convert D7 to base 10 using product rule

D7_{16} = D * 16^1 + 7 * 16^0

D = 13

So, we have:

D7_{16} = 13 * 16^1 + 7 * 16^0

D7_{16} = 215_{10}

Next convert 215 to base 2, using division rule

215 / 2 = 107 R 1

107/2 =53 R 1

53/2 =26 R1

26/2 = 13 R 0

13/2 = 6 R 1

6/2 = 3 R 0

3/2 = 1 R 1

1/2 = 0 R1

Write the remainders from bottom to top.

D7_{16} = 11010111_2

<em>Hence (b) is false</em>

(c)\ 13_{16} = 19_{10}

Convert 13 to base 10 using product rule

13_{16} = 1 * 16^1 + 3 * 16^0

13_{16} = 19

Hence; (c) is true

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