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2 years ago

What is the distance between the two points loacted at 3 , 8 and 10 , 8

Mathematics

2 answers:

damaskus [11]2 years ago

4 0

Answer:

Step-by-step explanation:

d=(10-3)^2+(8-8)^2=(7)^2+(0)^2=49

since it is in radical the the answer is 7

frozen [14]2 years ago

3 0

Answer:

Step-by-step explanation:

$\sqrt{(10-3)^{2}+(8-8)^{2}}$

$\sqrt{(49)+(0)} \\\sqrt{49}\\7$

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Answer:

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Step-by-step explanation:

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2 years ago

12. Find the measure of each interior angle of triangle QRT.

Veseljchak [2.6K]

Answer:

$\angle QRT=125.6\°$

$\angle RTQ=6.4\°$

$\angle TQR=48\°$

Step-by-step explanation:

It is important to remember that, by definition, the measure of an exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles.

In this case we can idenfity that the angle $17x$ is an exterior angle of the triangle QRT. Then:

$17x=\angle RTQ+\angle TQR$

Where:

$\angle RTQ=2x\\\\\angle TQR=48\°$

Substituting values and solving for "x", we get:

$17x=2x+48\\\\17x-2x=48\\\\15x=48\\\\x=3.2$

Then:

$17x=17(3.2)=54.4\°\\\\\\\angle RTQ=2(3.2)=6.4\°$

The sum of the interior angles of a triangle is 180°, therefore:

$\angle QRT+\angle RTQ+\angle TQR=180$

Solving for $\angle QRT$ , we get:

$\angle QRT=180-48-6.4=125.6\°$

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