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3 years ago

PLEASE HELP ME I AM DOING A TEST THAT WILL LEVEL UP MY GRADE IN MATH PLEASE

Mathematics

1 answer:

kipiarov [429]3 years ago

8 0

Answer:

i believe the answer is c

Step-by-step explanation:

but a also seems right as 3:6 is 1/2. despite that i belive c is correcr

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(-2.1m-5)+(3m-7)<br> Find the sum

wolverine [178]

Answer:

0.9 m − 12

Note:

Since there is no y value m can not be determine. Therefore finding the sum here can not be determined so instead you can try simplifying

4 0

3 years ago

Read 2 more answers

4x+4y=-20 and -3x-12y=-60

klasskru [66]

Answer:

(0,-5)

Step-by-step explanation:

3(4x+4y=20)

-3x-12y=-60

12x+12y=60

-3x-12y=-60

9x=0

x=0

4(0)+4y=-20

4y=-20

y=-5

5 0

3 years ago

Please help

DedPeter [7]

Answer:

Step-by-step explanation:

Given the expression $\sqrt{10} * \sqrt{10}$ . To find the product of this two values, the following steps must be followed.

According to one of the law of indices, $\sqrt{a} = a^{\frac{1}{2} }$

$\sqrt{10} * \sqrt{10}\\= 10^{\frac{1}{2} }* 10^{\frac{1}{2} }\\= 10^{\frac{1}{2}+\frac{1}{2}}\\ = 10^{1} \\= 10$

The product is 10

3 0

2 years ago

Read 2 more answers

Suppose you'd like to save enough money to pay cash for your next car. The goal is to save an extra $28,000 over the next 6 year

Anna35 [415]

Given:

• Amount to save, A = $28,000

• Time, t = 6 years

• Interest rate, r = 5.3% ==> 0.053

• Number of times compounded = quarterly = 4 times

Let's find the amount that must be deposited into the account quarterly.

Apply the formula:

$FV=P(\frac{(1+\frac{r}{n})^{nt}-1}{\frac{r}{n}})$

Where:

FV is the future value = $28,000

r = 0.053

n = 4

t = 6 years

Thus, we have:

$28000=P(\frac{(1+\frac{0.053}{4})^{4\times6}-1)}{\frac{0.053}{4}}$

Let's solve for P.

We have:

$\begin{gathered} 28000=P(\frac{(1+0.01325)^{24}-1}{0.01325}) \\ \\ 28000=P(\frac{(1.01325)^{24}-1)^{}}{0.01325}) \\ \\ 28000=P(\frac{1.371509114-1}{0.01325}) \\ \\ 28000=P(\frac{0.371509114}{0.01325}) \end{gathered}$

Solving further:

$28000=P(28.0384237)$

Divide both sides by 28.0384237:

$\begin{gathered} \frac{28000}{28.0384237}=\frac{P(28.0384237)}{28.0384237} \\ \\ 998.6=P \\ \\ P=998.6 \end{gathered}$

Therefore, the amount that must be deposited quarterly into the account is $998.60

ANSWER:

$998.60

8 0

1 year ago

119. Beatrice decides to deposit $100 per month at the end of every month in a bank with an annual interest rate of 5.5% compoun

sveta [45]

Answer:

Beatrice will accumulate $1230.72 at the end of the year.

Step-by-step explanation:

We can write:

$(1+\frac{0.055}{12})=z$

$100=C$ for deposits

The first month would have only the deposit reflected in her balance, then, expanding some steps of the calculation would yield:

$S_{1}=C\\S_{2}=Cz + C\\S_{3}=Cz^{2}+Cz + C\\S_{n}=Cz^{n-1} +...+Cz+C$

A geometric series is given by:

$1+x+...+x^{m}=\frac{x^{m+1}-1}{x-1}$

Translating our series to the short form:

$S_{n}=C(\frac{z^{n}-1}{z-1} )$

plugin in the values for the 12 month gives:

$S_{12}=100(\frac{(1+\frac{0.055}{12})^{12} -1}{\frac{0.055}{12}})=1230.7169$

3 0

3 years ago