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stich3 [128]
3 years ago
15

Find the solution to the system if inequalities

Mathematics
1 answer:
Kisachek [45]3 years ago
4 0

Answer:

y>\frac{2}{3} x+3

y>\frac{3}{5} x-2

Step-by-step explanation:

its not negative 3 its positive

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468

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YES. She is correct.

\dfrac{x}{16}=4\qquad\text{multiply both sides by 4}\\\\\not\!4^1\cdot\dfrac{x}{16\!\!\!\!\!\diagup_4}=4\cdot4\\\\\dfrac{x}{4}=16

Equations are equivalent

Their solutions:

\dfrac{x}{16}=4\qquad\text{multiply both sides by 16}\\\\x=4\cdot16\\\\\boxed{x=64}\\----------\\\\\dfrac{x}{4}=16\qquad\text{multiply both sides by 4}\\\\x=16\cdot4\\\\\boxed{x=64}


3 0
4 years ago
What is the solution set of y = x^2 + 2x + 7 and y = x + 7?
frozen [14]

Answer:

A,  I believe

Step-by-step explanation:

7 0
3 years ago
T= u+v/2 for u<br><br> •u= 2t+v<br> •u= 2t/v<br> •u= 2(t-v)<br> •u= 2t-v
ratelena [41]

Answer:

u=2t-v

Step-by-step explanation:

t=(u+v)÷2 |×2

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aniked [119]
The b value refers to the coefficient in front of the 2nd term, which is -8 in this case:
4 0
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