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1 year ago

Some Math i can’t helppp

Mathematics

1 answer:

mezya [45]1 year ago

7 0

Annually The amount after 10 years = $ 7247.295

quarterly compound after 10 years = $7393.5

Continuously interest =$7,419

Given:

P = the principal amount

r = rate of interest

t = time in years

n = number of times the amount is compounding.

Principal = $4500

time= 10 year

Rate = 5%

To find: The amount after 10 years.

The principal amount is, P = $4500

The rate of interest is, r = 5% =5/100 = 0.05.

The time in years is, t = 10.

Using the quarterly compound interest formula:

A = P (1 + r / 4)4 t

A= 4500(1+.05/4)40

A= 4500(4.05/4)40

A= 4500(1.643)

Answer: The amount after 10 years = $7393.5

Using the Annually compound interest formula:

A = P (1 + r / 100) t

A= 4500(1+5/100)10

A= 4500(105/100)10

Answer: The amount after 10 years = $ 7247.295

Using the Continuously compound interest formula:

e stands for Napier’s number, which is approximately 2.7183

$A=Pex^{rt} \\A=4500(e)^{.5} \\A= 4500(2.71)^{.5}$

A= $2,919

Answer: The amount after 10 years = $4500+$2,919=$7,419

More details :brainly.com/question/13307568

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Answer:

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Step-by-step explanation:

Solution:

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Let the original tour duration be for $x$ days.

So, for $x$ days the total expense = $360

Thus the daily expense in dollars can be given by = $\frac{360}{x}$

Tour extension and effect on daily expenses.

The tour is extended by 4 days.

Tour duration now = $(x+4)$ days

On extension, his daily expense is cut by $3

New daily expense in dollars = $(\frac{360}{x}-3)$

Total expense in dollars can now be given as: $(x+4)(\frac{360}{x}-3)$

Simplifying by using distribution (FOIL).

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So, we have the equation as:

$348-3x+\frac{1440}{x}=360$

Multiplying each term with $x$ to remove fractions.

$348x-3x^2+1440=360x$

Subtracting $348x$ both sides

$348x-348x-3x^2+1440=360x-348x$

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Adding $4x$ both sides.

$x^2+4x-480=-4x+4x$

$x^2+4x-480=0$

Solving using quadratic formula.

For a quadratic equation: $ax^2+bx+c=0$

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Plugging in values from the equation we got.

$x=\frac{-4\pm\sqrt{(4)^2-4(1)(-480)}}{2(1)}$

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So, we have

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$x=\frac{40}{2}$ and $x=\frac{-48}{2}$

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Since number of days cannot be negative, so we take $x=20$ as the solution for the equation.

Thus, the original duration of the tour = 20 days

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Step-by-step explanation:

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