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Sphinxa [80]
1 year ago
12

Some Math i can’t helppp

Mathematics
1 answer:
mezya [45]1 year ago
7 0

Annually The amount after 10 years = $ 7247.295

quarterly compound after 10 years = $7393.5

Continuously interest =$7,419

Given:

P = the principal amount

r = rate of interest

t = time in years

n = number of times the amount is compounding.

Principal =  $4500

time= 10 year

Rate = 5%

To find: The amount after 10 years.

The principal amount is, P = $4500

The rate of interest is, r = 5% =5/100 = 0.05.

The time in years is, t = 10.

Using the quarterly compound interest formula:

A = P (1 + r / 4)4 t

A= 4500(1+.05/4)40

A= 4500(4.05/4)40

A= 4500(1.643)

Answer: The amount after 10 years = $7393.5

Using the Annually  compound interest formula:

A = P (1 + r / 100) t

A= 4500(1+5/100)10

A= 4500(105/100)10

Answer: The amount after 10 years = $ 7247.295

Using the Continuously  compound interest formula:

e stands for Napier’s number, which is approximately 2.7183

A=Pex^{rt} \\A=4500(e)^{.5} \\A= 4500(2.71)^{.5}

A= $2,919

Answer: The amount after 10 years = $4500+$2,919=$7,419

More details :brainly.com/question/13307568

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Find the values of x and y that make k || j and <br> m || n.
telo118 [61]
Same side interior angles CONVERSE also called consecutive interior angle CONVERSE.
IF  (x - 30) + (x + 50) = 180 then, line line n || m.

x -  30 + x + 50 = 180
2x + 20 = 180
subtract 20 from both sides
2x = 160
divide both sides by 2
x = 80

IF (x - 30) + y = 180, then k || j.
(80 - 30) + y = 180
50 + y = 180
subtract 50 from both sides
y = 130


6 0
3 years ago
Read 2 more answers
A bottle of water contains 450ml. How many litres of water are there in 8 of these bottles
In-s [12.5K]

Answer:

3.6 litres

Step-by-step explanation:

1 bottle = 450ml

8 bottles = 450 × 8

               = 3600ml

1000ml = 1 litre

3600ml = 3.6 litres (3600÷1000)

6 0
3 years ago
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The bells are adding a new room to their house. The room will be a cube with volume 8000ft3. They are going to put in hardwood​
puteri [66]

Given:

Volume of a cubed room = 8000 cubic ft

Cost of floor hardwood = $10 per square foot

To find:

The total cost of floor hardwood.

Solution:

Let the each side of cubed room be x ft.

Volume of a cube is cube of its side.

Volume of a cubed room is 8000 cubic ft. So,

x^3=8000

Taking cube root on both sides.

x=20

So, length of each of room is 20 ft.

Area of base = length × breadth

So, area of base of room is

20\times 20=400\text{ ft}^2

It means, 400 sq ft  hardwood is required for the floor.

Cost of floor hardwood is $10 per square foot. So, total cost of hardwood floor is

400\times 10=4000

The hardwood floors will cost ​$4000.

4 0
3 years ago
Ayuda por favor
sergeinik [125]

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

<h3>¿Cómo determinar la medida de un lado de un triángulo desconocido?</h3>

En este problema tenemos un sistema formado por dos triángulos <em>similares</em>, la semejanza entre los dos triángulos se debe a la colinealidad entre los segmentos de línea AP' (triángulo <em>pequeño</em>) y AP'' (triángulo <em>grande</em>), así como de los lados AM y AB, así como los lados AN y AC, así como los <em>mismos</em> ángulos en la <em>misma</em> distribución. (Semejanza Lado - Ángulo - Lado)

En consecuencia, obtenemos las siguientes proporciones:

AP'/AP'' = MN/BC = 1/2     (1)

Finalmente, la proporción entre el triángulo AMN y el cuadrilátero BMNC es:

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)}{\frac{1}{2}\cdot (2\cdot a) \cdot  h - \frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)} = \frac{\frac{1}{4}\cdot a\cdot h }{a\cdot h - \frac{1}{4}\cdot a \cdot h }

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{4} }{\frac{3}{4} } = \frac{1}{3}

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

Para aprender sobre triángulos semejantes: brainly.com/question/21730013

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on the asymptotic behavior of the sample estimates of eigenvalues and eigenvectors of covariance matrices
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A complex mathematical topic, the asymptotic behavior of sequences of random variables, or the behavior of indefinitely long sequences of random variables, has significant ramifications for the statistical analysis of data from large samples.

The asymptotic behavior of the sample estimators of the eigenvalues and eigenvectors of covariance matrices is examined in this claim. This work focuses on limited sample size scenarios where the number of accessible observations is comparable in magnitude to the observation dimension rather than usual high sample-size asymptotic .

Under the presumption that both the sample size and the observation dimension go to infinity while their quotient converges to a positive value, the asymptotic behavior of the conventional sample estimates is examined using methods from random matrix theory.

Closed form asymptotic expressions of these estimators are obtained, demonstrating the inconsistency of the conventional sample estimators in these asymptotic conditions, assuming that an asymptotic eigenvalue splitting condition is satisfied.

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4 0
1 year ago
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