Answer:
Presumably you're solving for x here? Without further information we'll assume that.
With that in mind, x is approximately equal to 0.86 and -0.46
Step-by-step explanation:
Let's start by putting it in the usual ax² + bx + c format.
![5x^2- 2x = 2\\5x^2 - 2x - 2 = 0\\](https://tex.z-dn.net/?f=5x%5E2-%202x%20%3D%202%5C%5C5x%5E2%20-%202x%20-%202%20%3D%200%5C%5C)
let's solve it. First we'll multiply both sides by five, making the first term a perfect square:
![25x^2 - 10x - 10 = 0\\](https://tex.z-dn.net/?f=25x%5E2%20-%2010x%20-%2010%20%3D%200%5C%5C)
Now we'll add 11 to both sides:
![25x^2 - 10x + 1 = 11\\](https://tex.z-dn.net/?f=25x%5E2%20-%2010x%20%2B%201%20%3D%2011%5C%5C)
Which makes the left side a perfect square:
![(5x - 1)^2 = 11](https://tex.z-dn.net/?f=%285x%20-%201%29%5E2%20%3D%2011)
And now we can solve for x:
![(5x - 1)^2 = 11\\\\5x - 1 = \sqrt{11} \\\\5x = 1 + \sqrt{11}\\\\x = \frac{1 + \sqrt{11}}{5}](https://tex.z-dn.net/?f=%285x%20-%201%29%5E2%20%3D%2011%5C%5C%5C%5C5x%20-%201%20%3D%20%20%5Csqrt%7B11%7D%20%5C%5C%5C%5C5x%20%3D%201%20%2B%20%5Csqrt%7B11%7D%5C%5C%5C%5Cx%20%3D%20%5Cfrac%7B1%20%2B%20%5Csqrt%7B11%7D%7D%7B5%7D)
Note that there's no apparent way of drawing the ± symbol when editing equations, so take that + sign as actually being ±.
That gives us two answers:
![x = \frac{1 - \sqrt{11}}{5}\\\\x \approx \frac{1 - 3.32}5\\\\x \approx \frac{-2.32}5\\\\x \approx -0.46](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B1%20-%20%5Csqrt%7B11%7D%7D%7B5%7D%5C%5C%5C%5Cx%20%5Capprox%20%5Cfrac%7B1%20-%203.32%7D5%5C%5C%5C%5Cx%20%5Capprox%20%5Cfrac%7B-2.32%7D5%5C%5C%5C%5Cx%20%5Capprox%20-0.46)
Answer:
![\frac{x^{2} }{10} -\frac{y^{2} }{15} = 1](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D%20%7D%7B10%7D%20-%5Cfrac%7By%5E%7B2%7D%20%7D%7B15%7D%20%3D%201)
Step-by-step explanation:
since the foci is (±5,0), the standard form of the hyperbola would be ![\frac{x^{2} }{a^{2} } -\frac{y^{2} }{b^{2} } = 1](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D%20%7D%7Ba%5E%7B2%7D%20%7D%20-%5Cfrac%7By%5E%7B2%7D%20%7D%7Bb%5E%7B2%7D%20%7D%20%3D%201)
directics = ±a^2/c
±2 = ±a^2/5
a^2 = 10
a^2+b^2=c^2
b^2 = c^2-a^2 =5^2-10 = 15
Answer:
0; 3.
Step-by-step explanation:
1) if to substitute x=1 into the given equation, it is possible to calculate the value of 'm':
1-m²-m+1=0; ⇔ m²+m-2=0; ⇒ m₁=-2; m₂=1;
2) if m=-2 and m=1, then the initial equation is:
x²-4x+3=0 or x²-x=0;
3) according to the item 3), the 2d root is:
x₂=3 or x₂=0.
Answer:
Step-by-step explanation:
Answer:
15.15
Step-by-step explanation:
Divide 15 by 0.99