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Alenkinab [10]
2 years ago
6

6. Which of the following is true about the

Mathematics
1 answer:
Gnom [1K]2 years ago
5 0
C.
Y=mx + b is the formula (M being slope, and B being the y intercept) always start by going up or down by what the y-intercept number is, if it’s -9 you go down the y axis 9 numbers from the origin (0,0) and slope (m) is always better put in a fraction-5x is better put in -5/1x
Think of the top number of the fraction as ‘up/down’ and the bottom number as ‘over’ if the top number is negative you will go down from the y-intercept number that many times, the bottom number is how many spots you go over from that number , it is always to the right.
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If the volume of the right prism shown is 27 ft3, then h = __feet.
konstantin123 [22]

Answer:

h=6

Step-by-step explanation:

To find the volume of a right angle prism-

Find area of cross-section, in this case an isoscles triangle so we know that both of the parallel lines are 3ft

To find the area of the cross-section, do:

3 x 3 = 9

9 ÷ 2 = 4.5 (Area of cross-section)

Since we don't know the length of h, we need do:

27^3 ÷ 4.5 = 6

Therefore 6 is h

Hope I explained it okay:)

3 0
2 years ago
00010000.00100010.10000100.10000001
Sonja [21]

Answer:

Step-by-step explanation:

What am I supposed to say?

4 0
2 years ago
Tell whether the triangles are similar.Explain.
Burka [1]

Answer: 13. yes 14. no

Step-by-step explanation:

13. same angles sized down

14. different angles sized down

3 0
2 years ago
I don't know how to solve this please help.
snow_lady [41]

Simplify the expression.

Your answer is: 3738

3 0
2 years ago
Read 2 more answers
Change each of the following points from rectangular coordinates to spherical coordinates and to cylindrical coordinates.
FromTheMoon [43]

Answer and Step-by-step explanation: Spherical coordinate describes a location of a point in space: one distance (ρ) and two angles (Ф,θ).To transform cartesian coordinates into spherical coordinates:

\rho = \sqrt{x^{2}+y^{2}+z^{2}}

\phi = cos^{-1}\frac{z}{\rho}

For angle θ:

  • If x > 0 and y > 0: \theta = tan^{-1}\frac{y}{x};
  • If x < 0: \theta = \pi + tan^{-1}\frac{y}{x};
  • If x > 0 and y < 0: \theta = 2\pi + tan^{-1}\frac{y}{x};

Calculating:

a) (4,2,-4)

\rho = \sqrt{4^{2}+2^{2}+(-4)^{2}} = 6

\phi = cos^{-1}(\frac{-4}{6})

\phi = cos^{-1}(\frac{-2}{3})

For θ, choose 1st option:

\theta = tan^{-1}(\frac{2}{4})

\theta = tan^{-1}(\frac{1}{2})

b) (0,8,15)

\rho = \sqrt{0^{2}+8^{2}+(15)^{2}} = 17

\phi = cos^{-1}(\frac{15}{17})

\theta = tan^{-1}\frac{y}{x}

The angle θ gives a tangent that doesn't exist. Analysing table of sine, cosine and tangent: θ = \frac{\pi}{2}

c) (√2,1,1)

\rho = \sqrt{(\sqrt{2} )^{2}+1^{2}+1^{2}} = 2

\phi = cos^{-1}(\frac{1}{2})

\phi = \frac{\pi}{3}

\theta = tan^{-1}\frac{1}{\sqrt{2} }

d) (−2√3,−2,3)

\rho = \sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}+3^{2}} = 5

\phi = cos^{-1}(\frac{3}{5})

Since x < 0, use 2nd option:

\theta = \pi + tan^{-1}\frac{1}{\sqrt{3} }

\theta = \pi + \frac{\pi}{6}

\theta = \frac{7\pi}{6}

Cilindrical coordinate describes a 3 dimension space: 2 distances (r and z) and 1 angle (θ). To express cartesian coordinates into cilindrical:

r=\sqrt{x^{2}+y^{2}}

Angle θ is the same as spherical coordinate;

z = z

Calculating:

a) (4,2,-4)

r=\sqrt{4^{2}+2^{2}} = \sqrt{20}

\theta = tan^{-1}\frac{1}{2}

z = -4

b) (0, 8, 15)

r=\sqrt{0^{2}+8^{2}} = 8

\theta = \frac{\pi}{2}

z = 15

c) (√2,1,1)

r=\sqrt{(\sqrt{2} )^{2}+1^{2}} = \sqrt{3}

\theta = \frac{\pi}{3}

z = 1

d) (−2√3,−2,3)

r=\sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}} = 4

\theta = \frac{7\pi}{6}

z = 3

5 0
3 years ago
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