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WARRIOR [948]
2 years ago
12

Jesse sold cupcakes and cookies yesterday. Each cupcake sold for $1.50 and each cookie sold for $0.25. At the end of the day, Je

sse had sold $37.75 worth of cookies and cupcakes. If he sold 56 cupcakes and cookies combined, how many cupcakes were sold and how many cookies were sold?
Mathematics
1 answer:
ale4655 [162]2 years ago
7 0

Answer: 19 cupcakes and 37 cookies were sold.

Step-by-step explanation:

Let x represent the number of cupcakes that Jesse sold yesterday.

Let y represent the number of cookies that Jesse sold yesterday.

If he sold 56 cupcakes and cookies combined, it means that

x + y = 56

Each cupcake sold for $1.50 and each cookie sold for $0.25. At the end of the day, Jesse had sold $37.75 worth of cookies and cupcakes. This means that

1.5x + 0.25y = 37.75 - - - - - - - - - - -1

Substituting x = 56 - y into equation 1, it becomes

1.5(56 - y) + 0.25y = 37.75

84 - 1.5y + 0.25y = 37.75

- 1.5y + 0.25y = 37.75 - 84

- 1.25y = - 46.25

y = - 46.25/ - 1.25

y = 37

x = 56 - y = 56 - 37

x = 19

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