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PSYCHO15rus [73]
3 years ago
9

Find the value of x. If necessary, round your answer to the nearest tenth. The figures are not drawn to scale.

Mathematics
1 answer:
REY [17]3 years ago
4 0

Answer:

9.93

Step-by-step explanation:

Secant-Tangent theorem tells us that the product of the secant segment with its external segment is equal to the square of the tangent segment.

From the diagram, we can say (let the unknown part of secant line, the part left of the segment length 5, be y):

(15+y)(10) = 17^2

Solving for y we get:

(15+y)(10) = 17^2\\150+10y=289\\10y=289-150\\10y=139\\y=13.9

Now we can use the chord theorem to solve for x. Chord theorem tells us that when 2 intersecting chords create 4 segments, the product of the individual chord segments are equal. Thus we can say:

5 * 13.9 = 7 * x

Now solving, we get:

5 * 13.9 = 7 * x\\69.5=7x\\x=\frac{69.5}{7}\\x=9.93

Thus x = 9.93

last answer choice is right.

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Suppose that c (x )equals 7 x cubed minus 70 x squared plus 13 comma 000 x is the cost of manufacturing x items. Find a producti
Leno4ka [110]

Answer:

<h3>A production level that will minimize the average cost of making x items is x=5.</h3>

Step-by-step explanation:

Given that

c(x)=7x^3-70x^2+13,000x

is the cost of manufacturing x items

<h3>To find a production level that will minimize the average cost of making x items:</h3>

The average cost per item is f(x)=\frac{c(x)}{x}

Now  we get f(x)= 7x^2-70x+13000

<h3> f(x) is continuously differentiable for all x</h3>

Here x≥0 since it represents the number of items.,

Put x=0 in 7x^2-70x+13000

For x=0 the average cost becomes 13000

f(0)=7(0)^2-70(0)+13000

=13000

<h3>∴ f(0)=13000</h3><h3>To find Local extrema :</h3>

Differentiating f(x) with respect to x

f^{\prime} (x)=14x-70=0

14x=70

x=\frac{70}{14}

<h3>∴  x=5 gives the minimum average cost .</h3><h3>At x=5 the average cost is </h3>

f(5)=7(5)^2-70(5)+13000

=12825

<h3>∴ f(5)=12825 which is smaller than for x=0 is 13000</h3><h3>∴ f(x) is decreasing between 0 and 5 and it is increasing after 5.</h3>
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3 years ago
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What’s the area of the shaded region???
gizmo_the_mogwai [7]

Answer:

90

Step-by-step explanation:

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I NEED HELP AND IM ON A TIMED TEST
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This Question is not Complete

Complete question

The number of absences per student in each of two classes is shown on the dot plots below.

A dot plot titled Number of absences per student in Misses Anderson's class. The number line goes from 0 to 6. There is 1 dot above 0, 3 above 1, 3 above 2, 3 above 3, 1 above 4, and 0 above 5 and 6.

A dot plot titled Number of absences per student in Misses Bergot's class. The number line goes from 0 to 6. There is 1 dot above 0, 1 above 1, 2 above 2, 3 above 3, 2 above 4, 1 above 5, and 1 above 6.

Which statements accurately compare the two data sets? Select three options.

a. The mean number of absences is greater in Mrs. Anderson’s class.

b. The mean number of absences is greater in Mrs. Bergot’s class.

c. There is more variability in Mrs. Anderson’s data set.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Answer:

b. The mean number of absences is greater in Mrs. Bergot’s class.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Step-by-step explanation:

From the above data given in the question and the options given to us, we can observe from the comparison of both the number of absences in Mrs Bergot's class to that in Mrs Anderson's class, there will be a presence of variation in the data of one of the classes and that class happens to be Mrs Bergot's class.

The appropriate statistical tool that we can be used to determine and measure the centre of variability of the data is Mean and Mean Absolute Deviation.

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3 years ago
4 students measure their height. Their heights measure 184 cm, 192 cm, 164 cm, and 200 cm. What is the mean height of the studen
melomori [17]
The mean is the average, which is the sum of all the numbers divided by the total numbers there are. I will add them up for you, and then work from there.
184 + 192 + 164 + 200 = 740.
There is 740cm total, but now we need to divide by how many students we have. We have 4 students total.
740/4 = 185.
Your average (mean) height of the students is 185cm.
I hope this helps!
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Answer:

Step-by-step explanation:

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2    -1      0      1     2    3    4

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4    -3     -2    -1     0     1    2

5    -4     -3    -2    -1     0    1

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