Disregarding air friction, the distance traveled by an object due to gravity is : H = 0.5*g*t^2. g is the gravitational constant at the surface of earth.
g= 9.81 m/s^2
After 3 seconds, Distance = .5*9.81*9 = 44.15 meters traveled.
Since it was dropped from a height of 90 meters, the current height is 90 - 44.15 = (a) 45.85 meters
(b) It has to travel 90 meters to hit the ground . So we must find t
Using the same equation
t = (2*H/g)^.5
t = (2*90/g)^.5 = 4.28 seconds until it hits the ground
(A) E, D, G, A, B, C
(B) AB, BC, AC
(C) <span>AB, BC, AC</span>
(D)an angle
(E) Angle EDG, Angle GDE
(A)75
(B) Acute
Answer: 199 square yards
Step-by-step explanation:
If you break it down into 3 rectangles it’ll be easier to find the answer. Multiply it by H x W. First you do the 6 x 10. And then afterwards add the extra 5 to the 6 and it’ll make the
H = 11, and the W is 4. And then add the last 3 to H and it’ll make it 19 and the last W is 5
6 x 10 = 60
11 x 4 = 44
19 x 5 = 95
Total of 199
Hope this helps :)
Given:
value of the test statistic is t20 = 1.95
corresponding p-value of 0.0653 at the 5% significance level
No, I can't conclude that the correlation coefficient differs from zero because the p-value, which is 0.0653 exceeds 0.05.
The correlation coefficient differs from zero when the p-value is less than 0.05.
Answer:
15 sec
Step-by-step explanation:
Data:
let m = 600 kg
b = 50
the differential equation will be:
