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3 years ago

What is the least common multiple of 16, 24 and 30?

Mathematics

2 answers:

r-ruslan [8.4K]3 years ago

6 0

All of the numbers are even so 2

Answer: 2

qwelly [4]3 years ago

4 0

2 is the right answer

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use the line graph to answer the question 9 and 10 how much did the temperature change from Sunday High to Mondays High ? what w

Marizza181 [45]

Answers:

How much did the temperature change from Sunday High to Mondays High?

Change = 4 °C

What was the difference between the high temperatures on Friday and Wednesday?

Difference = 10 °C

Explanation:

Taking into account the graph, we get that the high temperature each day is:

Sunday: -10°C

Monday: -6 °C

Tuesday: - 4 °C

Wednesday: -6 °C

Thursday: 0 °C

Friday: 4 °C

Saturday: -2 °C

So, the change from Sunday High to Mondays High can be calculated as:

Change = Monday - Sunday

Change = -6 °C - (- 10 °C)

Change = -6 °C + 10 °C

Change = 4 °C

In the same way, the difference between the high temperatures on Friday and Wednesday can be calculated as:

Difference = Friday - Wednesday

Difference = 4 °C - (-6 °C)

Difference = 4 °C + 6 °C

Difference = 10 °C

Therefore, the answers are:

How much did the temperature change from Sunday High to Mondays High?

Change = 4 °C

What was the difference between the high temperatures on Friday and Wednesday?

Difference = 10 °C

6 0

1 year ago

Answer correct you get brainliest answer

zloy xaker [14]

Answer:

$y = {x}^{2} - 2$

Or if you want with the value of h too.

$y = {(x - 0)}^{2} - 2$

Step-by-step explanation:

$y = a {(x - h)}^{2} + k$

Find the value of h and k by using the formula.

$h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{4a}$

From y = x²-2

$a = 1 \\ b = 0 \\ c = - 2$

Substitute these values in the formula.

$h = - \frac{0}{2(1)} \\ h = 0$

Therefore, h = 0.

$k = \frac{4(1)( - 2) - {0}^{2} }{4(1)} \\ k = \frac{ - 8}{4} \\ k = - 2$

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

$y = a {(x - h)}^{2} + k \\ y = 1 {(x - 0)}^{2} - 2 \\ y = {(x)}^{2} - 2 \\ y = {x}^{2} - 2$

These type of equation where b = 0 can also be both standard and vertex form.

4 0

3 years ago

For each sentence, write an equation.

Dafna11 [192]

A) x/6=9
Subtract 6 from both sides, x=3

B) x/-4=-3
Add 4 to both sides, x=1

C) x/-5=7
Add 5 to both sides, x=12

5 0

2 years ago

Write the expression in algebraic form. [hint: sketch a right triangle.] tan(arcsec(x/3))

WARRIOR [948]

Sketch a right triangle having adjacent side(A) is given as “3”, hypotenuse side (H) is “x” and assigning angle “a” as the angle between A and H. Using Pythagorean theorem, you will get “square root of x-squared minus 9” as the opposite side (O). Using SOH CAH TOA function, and since secant is the reciprocal of cosine, sec(a) = x/3. Thus, a = arcsec(x/3). The remaining expression tan(a) is Opposite side over Adjacent side which is equal to “square root of x^2 - 9” over "3". Therefore, the algebraic expression would be: tan(arcsec(x/3)) = “sqrt (x^2 -9)” /3. Different answers can be made depending on which side you consider the “3” and “x”.

6 0

3 years ago

34789 divided by 54 equals what

AleksAgata [21]

644.240741
:).,.....................

3 0

3 years ago