Prove that: (12^13–12^12+12^11)(11^9–11^8+11^7) is divisible by 3, 7, 19, and 37. The answer should be like: x^b*3*7*19*37. Also
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Answer:
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given that a× 70 = b
Dividing 'a' into both sides, we get
⇒
we have to find the value
= 3× 70
= 210
(A) The mean is 82
(B) The mean absolute deviation is approximately 9.71
(D) The IQR is 11
<u>Explanation:</u>
<u />
(A) 89, 87, 54, 78, 87, 99, 80
Mean of the data =
Therefore, mean of the data is 82
(B) The mean absolute deviation, MAD is
data - 54, 78, 80, 87, 87, 89, 99
Mean of the data, x' is 82
|x - x'| : 54 - 82 = 28
78 - 82 = 4
80 - 82 = 2
87 - 82 = 5
87 - 82 = 5
89 - 82 = 7
99 - 82 = 17
Total of |x - x'| = 68
MAD = |x - x'| / n
MAD = 68/7
MAD = 9.71
(D) IQR is the interquartile range
Data = 54, 78, 80, 87, 87, 89, 99
IQR = median of lower quartile range - median of upper quartile range
IQR = 89 - 78
IQR = 11