The given equation with t -1 is:
(t – 1)^3 + 6 (t – 1)^2 + 12 (t – 1) + 8
Expand each term before combining for easier visualization:
(t – 1)^3 = t^3 – 3 t^2 + 3t – 1
6 (t – 1)^2 = 6 t^2 – 12 t + 6
12 (t – 1) = 12 t - 12
Then substitute and combine:
-> t^3 – 3 t^2 + 3t – 1 + 6 t^2 – 12 t + 6 + 12 t – 12 + 8
t^3 + 3 t^2 + 3 t + 1 (ANSWER)
- 1 1/10 + (-1 2/5)
- 1 1/10 + (-1 4/5)
-2 5/10
-2 1/2
Answer:
1/6
Step-by-step explanation:
So we are subtracting a negative which is the same as adding. Our equation becomes -1/3+1/2. To add fractions we need a common denominator (the denominator of a fraction is the number on the bottom) To fine the least common denominator we need to find the lowest number that both 3 and 2 go into which is 6. Then we will multiply each fraction by the number that will give us 6 for a denominator which is 2 for -1/3 and 3 for 1/2. So -1/3 times 2 is -2/6 and 1/2 times 3 is 3/6. Our equation is now -2/6+3/6. Now we will add the numerators ( the numerator is the number on the top of the fraction) and the denominators stay the same when adding or subtraction fractions -2/6+3/6=1/6
I hope this helps and please let me know if there is anything you are confused about or is still unclear, I will be happy to help!
Answer:
-103
243
Step-by-step explanation:
(q•r)(5) = q(r(5))
r(5) = 2(5²) + 1 = 51
q(51) = -2(51) - 1 = -103
(r•q)(5) = r(q(5))
q(5) = -2(5) - 1 = -11
r(-11) = 2(-11)² + 1 = 243
Answer:Bet bro how you want it
Step-by-step explanation: sloppy or clean?
