Question

ACT scores are normally distributed and from 2015 to 2017, the mean was 20.9 with a standard deviation of 5.6.

Answer 1

Answer:

You need a z-score of at least 1.09 to get accepted.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$, the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 20.9, \sigma = 5.6$

To get accepted into OSU, you need at least a 27. What is the z-score you need to get accepted?

We need to find Z when X = 27. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{27 - 20.9}{5.6}$

$Z = 1.09$

You need a z-score of at least 1.09 to get accepted.