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kramer
3 years ago
12

When compared to combination​ e, combination c provides ▼ the same less more satisfaction to the consumer?

Business
1 answer:
Volgvan3 years ago
6 0

B is the answer. There you go
You might be interested in
greene co. has pretax book income for the year ended december 31, 2019 in the amount of 265000 and has a tax rate of 30%. Deprec
Gennadij [26K]

Answer:

Pre-tax book income $265,000

Less depreciation additional charge $14,500

Taxable income $250,500

Tax liability at 30% = $75,150

8 0
3 years ago
question content area for the year ended december 31, orion, inc. mistakenly omitted adjusting entries for $1,500 of supplies th
Oduvanchick [21]

Errors will have a $2,300 overstatement of net income on revenues, costs, and net income.

The amount earned by an individual or business after costs, allowances, and taxes is referred to as net income. Net income in the company is the amount that remains after all costs, such as salaries and wages, the cost of goods or raw materials, and taxes, have been paid.

Net income = Total revenue - total expenses

where,

Total revenue = Unearned revenue = $4,200

Total Expense = Supplies expense + insurance expense = $1,500 + $5,000 = $6,500

Net Income = Total revenue - Total Expenses = $4,200 - $6,500

Net Income = -$2,300

Therefore, there's an overstatement of $2300 in Net Income.

To know more about Net Income, refer to this link:

brainly.com/question/6391667

#SPJ9

6 0
1 year ago
The following is the sales budget for Coore, Inc., for the first quarter of 2019. January February March Sales budget $168,000 $
nekit [7.7K]

Answer:

a. Sales for November = $192,666.67

b. Sales for December = $390,500

c. Cash collections for:

January = $216,200

February = $213,075

March = $191,750

Explanation:

First consider the following information:

Credit sales are collected as follows:

65% in the month of the sale

20% in the month after the sale

15% in the second month after the sale

a. To calculate sales for November, note that the account receivable balance at the end of the previous quarter is from the sales of the previous two months (November and December), of these sales, we are told that $78,100 is from December sales, therefore to calculate the amount from November sales = 107,000 - 78,100 = $28,900.

Next, we are told that the 15% of sales are collected is the second month following sales, and January is the second month following the November sales from the previous quarter, therefore, the $28,900 from the previous November sales is 15% of the original sales, and the original sale is calculated thus:

Let sale for November be N

15% of N = 28,900

15/100 × N = 28,900

0.15N = 28,900

∴ N = 28,900 ÷ 0.15 = $192,666.67 ( to 2 decimal places)

b. The $78,100 which was uncollected December sales is 20% of the original sales, since December is the one month away from the beginning of the new quarter, and 20% of sales is collected in the month following sales. Therefore December sales is calculated as follows:

Let December sales be D

20% of D = 78,100

0.20 × D = 78,100

∴ D = 78,100 ÷ 0.20 = $390,500

c.

i. Cash collections in January

from previous quarter = $107,000

from January's sales = 65% of January sales

= 0.65 × 168,000 = 109,200

Total cash collection in January = $216,200

ii. cash collections in February:

From December sales = 15% of December sales ( Fabruary is 2 months following December sales)

= 0.15 × 390,500 = $58,575

from January's sales = 20% of January sales (February is the month following January's sales)

= 0.20 × 168,000 = $33,600

from February's sale = 65% of February's sales

= 0.65 × 186,000 = $120,900

Total cash collections in February = 58,575 + 33,600 + 120,900 = $213,075

iii. Cash collections in March

From January's sale = 15% of January's sales

= 0.15 × 168,000 = $25,200

from February's sale = 20% of February's sale

= 0.20 × 186,000 = $37,200

From March's sale = 65% of March's sale

= 0.65 × 199,000 = $129,350

∴ Total cash collections for March = 25,200 + 37,200 + 129,350 = $191,750

7 0
3 years ago
Gloria just started working for GlenMack. As part of her signing bonus, she received 20 shares of GlenMack stock. Gloria is exci
EastWind [94]

Answer:

Public Company

Explanation:

In the given case, since it is mentioned that Gloria working for GlenMack now as a part of the signing bonus she received twenty shares from the stock of GlenMack now she is excited to contribute to the company and also wants to track the shares value on the new york stock exchange so here the Glenmust must be public company as the stock are listed on the stock exchange

So the same is to be relevant

3 0
3 years ago
An oil refinery is located on the north bank of a straight river that is 3km wide. A pipeline is to be constructed from the refi
Mariulka [41]

Answer:

$6,598,076.21

Explanation:

<h2>THE KEY IS TO FIND OUT THE COST FUNCTION, the calculations are very easy!!!</h2><h2></h2><h3>In order to find the cost function, take a look at the drawing attached. </h3>

We can see the river (sort of) that is 3 km wide and the storage tanks on the other side of the river 8 km apart.

<h3 />

Laying pipes under (across) the river costs 1,000,000 the km & laying pipes over land costs 500,000 per km.

<h3 /><h3>So basically the cost function is 1,000,000 multiplied by something plus 500,000 multiplied by another something.</h3><h3 />

The distance across the river can be found by using Pythagoras Theorem. A side is 3 km the other is unknown, so we call it X. And it is equal to:

\sqrt{3^{2} +x^{2}}=\\\sqrt{9 +x^{2}}

And we multiply it by 1,000,000; the cost of laying pipe under the river, the we get:

1000000\sqrt{9+x^{2}

The distance over the land is (8-x), as we can see in the drawing. So we multiply it by its cost, 500,000. And we get 500,000(8-x).

So the cost function f(x) would be:

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)

<h2>From here, we just have to differentiate and the derivative found must be equal to zero in order to minimize cost. </h2><h3>The value of x when the derivative is zero is plugged in the original function to get the cost.</h3><h3 /><h2>LET'S DO THIS</h2>

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(x)=1000000(9+x^{2})^{1/2}+4000000-500000x\\f'(x)=\frac{1}{2} 1000000(9+x^{2})^{-1/2}(2x)-500000\\\\f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000

<h2>f'(x)=0</h2>

f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000=0\\\frac{1000000x}{\sqrt{9+x^2}}  = 500000\\\frac{2x}{\sqrt{9+x^2}}  = 1\\2x={\sqrt{9+x^2}}\\4x^2=9+x^2\\3x^2=9\\x^2=3\\x=\sqrt{3} \\

And we plug square root of 3 in the original cost function  ad we get

f(\sqrt{3} )=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(\sqrt{3})=1000000\sqrt{9+(\sqrt{3} )^{2}} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{9+3} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{12}+500000(6.27)\\f(\sqrt{3})=1000000(3.46)+500000(6.27)\\f(\sqrt{3})=3464101.62+3133974.60\\f(\sqrt{3})=6598076.21\\

<h2>so the minimal cost is $6,598,076.21</h2><h2 /><h3 />

6 0
4 years ago
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