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4 years ago

Which equation is equivalent to f(x) = 16x4 – 81 = 0?

Mathematics

2 answers:

Vesna [10]4 years ago

5 0

Answer:

The equivalent expression is:

$16x^4-81=(4x^2-9)(4x^2+9)$

Step-by-step explanation:

We have been given the equation:

$f(x)=16x^4-81=0$

Equivalent expression can be computed by solving the expression ai its maximum.

We can factorize the given equation:

By using $a^2-b^2=(a+b)(a-b)$

Here, $a=4x^2,b=9$

Hence, we get the equation below:

$16x^4-81=(4x^2-9)(4x^2+9)$

Therefore, the equivalent expression is:

$16x^4-81=(4x^2-9)(4x^2+9)$

Alenkasestr [34]4 years ago

5 0

Answer:

The answer is (4x2+9)(4x2-9)=0

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What is the parent function of the following function? f(x) = 3(5)*

Vlad [161]

I think it’s 15 f(x) 15

7 0

3 years ago

(i) 3 (a + 5b) + a (a + 4) (ii) y (10 - y) + 3 (y - 2) (iii) 2 (8a - 5b) + 3 (5a - 12) (iv) 3 (y - 3) + ( 8 - 6y + x) (v) a (a -

AveGali [126]

Answer:

$3 (a + 5b) + a (a + 4) = a^2 + 7a + 15b$

$y (10 - y) + 3 (y - 2) = - y^2+13y - 6$

$2 (8a - 5b) + 3 (5a - 12) = 31a -10b - 36$

$3 (y - 3) + ( 8 - 6y + x) = -3y + x-1$

$a (a - 2b) + b (b + 2a - c) =a^2 + b^2 - bc$

$5 (x - y + z) + (4x + 3y) =9x - 2y +5z$

Step-by-step explanation:

Solving (i):

$3 (a + 5b) + a (a + 4)$

Open brackets

$3 (a + 5b) + a (a + 4) = 3a + 15b + a^2 + 4a$

Collect like terms

$3 (a + 5b) + a (a + 4) = a^2 + 4a+3a + 15b$

$3 (a + 5b) + a (a + 4) = a^2 + 7a + 15b$

Solving (ii)

$y (10 - y) + 3 (y - 2)$

Open bracket

$y (10 - y) + 3 (y - 2) = 10y - y^2 + 3y - 6$

Collect like terms

$y (10 - y) + 3 (y - 2) = - y^2+10y + 3y - 6$

$y (10 - y) + 3 (y - 2) = - y^2+13y - 6$

Solving (iii)

$2 (8a - 5b) + 3 (5a - 12)$

Open bracket

$2 (8a - 5b) + 3 (5a - 12) = 16a -10b + 15a - 36$

Collect like terms

$2 (8a - 5b) + 3 (5a - 12) = 16a+ 15a -10b - 36$

$2 (8a - 5b) + 3 (5a - 12) = 31a -10b - 36$

Solving (iv)

$3 (y - 3) + ( 8 - 6y + x)$

Open bracket

$3 (y - 3) + ( 8 - 6y + x) = 3y - 9 + 8 - 6y + x$

Collect like terms

$3 (y - 3) + ( 8 - 6y + x) = 3y - 6y + x- 9 + 8$

$3 (y - 3) + ( 8 - 6y + x) = -3y + x-1$

Solving (v):

$a (a - 2b) + b (b + 2a - c)$

Open bracket

$a (a - 2b) + b (b + 2a - c) =a^2 - 2ab + b^2 + 2ab - bc$

Collect like terms

$a (a - 2b) + b (b + 2a - c) =a^2 + 2ab- 2ab + b^2 - bc$

$a (a - 2b) + b (b + 2a - c) =a^2 + b^2 - bc$

Solving (vi)

$5 (x - y + z) + (4x + 3y)$

Open brackets

$5 (x - y + z) + (4x + 3y) =5x - 5y +5z+4x +3y$

Collect like terms

$5 (x - y + z) + (4x + 3y) =5x +4x +3y- 5y +5z$

$5 (x - y + z) + (4x + 3y) =9x - 2y +5z$

6 0

3 years ago

The ratio of Wei Ling's age to Wei Xuan's age 5 years ago was 2: 5. In 9 years

Archy [21]

Answer:

15 years old

Step-by-step explanation:

Start by defining the variables that we are going to use throughout our working:

Let the current age of Wei Ling and Wei Xuan be L and X years old respectively.

Next, form equations using the given information.

5 years ago

Wei Ling: (L -5) years old

Wei Xuan: (X -5) years old

Given that the ratio of Wei Ling's age to that of Wei Xuan's is 2: 5,

$\frac{ L - 5}{X - 5} = \frac{2}{5}$

Cross multiply:

2(X -5)= 5(L -5)

Expand:

2X -10= 5L -25

2X= 5L -25 +10

2X= 5L -15 -----(1)

9 years time

Wei Ling: (L +9) years old

Wei Xuan: (X +9) years old

Given that the ratio of Wei Ling's age to that of Wei Xuan is 3: 4,

$\frac{L + 9}{X + 9} = \frac{3}{4}$

Cross multiply:

3(X +9)= 4(L +9)

Expand:

3X +27= 4L +36

3X= 4L +36 -27

3X= 4L +9 -----(2)

Let's solve using the elimination method.

(1) ×3:

6X= 15L -45 -----(3)

(2) ×2:

6X= 8L +18 -----(4)

(3) -(4):

6X -6X= 15L -45 -(8L +18)

0= 15L -45 -8L -18

0= 7L -63

7L= 63

L= 63 ÷7

L= 9

Substitute L= 9 into (1):

2X= 5(9) -15

2X= 45 -15

2X= 30

X= 30 ÷2

X= 15

Thus, Wei Xuan is 15 years old now.

6 0

3 years ago

Use the given information to determine the exact trigonometric value. (in the image attached)

notka56 [123]

Answer:

OPTION B: $\frac{-2\sqrt{5}}{5}$

Step-by-step explanation:

Given $cot \theta = -\frac{\sqrt{5}}{2}$

We know that, $\frac{1}{cot \theta} = tan \theta$

$\implies tan \theta = \frac{1}{-\frac{\sqrt{5}}{2}}$

$= -\frac{2}{\sqrt{5}}$

Multiplying and dividing by $\sqrt{5}$ , we get:

$tan \theta = - \frac{2 \sqrt{5}}{\sqrt{5}\times \sqrt{5}}}$

$\implies tan \theta = -\frac{2\sqrt{5}}{5}$

Hence, OPTION B is the answer.

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3 years ago

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3 years ago