Answer:
n=3
Step-by-step explanation:
Hey there! I'm happy to help!
Let's have the capacity be c. The tank is currently at 4/5c. We subtract 190 and then we are at 1/6c. Let's set this up as an equation and solve it.
4/5c-190=1/6c
We want to get the c all by itself to see the capacity of the tank. Let's get all of the c values on the left side of the equation and the numbers on the right by using inverse operations.
4/5c-190=1/6c
Add 190 to both sides.
4/5c=1/6+190
Subtract 1/6 from both sides.
19/30c=190
Divide both sides by 19/30.
c=300
So, the capacity of the tank is 300 liters of water.
Have a wonderful day and keep on learning! :D
Answer:
Step-by-step explanation:
x^2-1=0
Add 1 to both sides of the equation.
x^2=
1
Take the square root of both sides of the equation to eliminate the exponent on the left side.
x
=
±
√
1
Any root of 1 is x
=
±
1
First, use the positive value of the ±
to find the first solution.
x=
1
Next, use the negative value of the ±
to find the second solution.
x
=
−
1
The complete solution is the result of both the positive and negative portions of the solution.
x
=
1
,
−
1
Answer:
x = -25
Step-by-step explanation:
![3 - \frac{x}{5} = 8](https://tex.z-dn.net/?f=3%20-%20%20%5Cfrac%7Bx%7D%7B5%7D%20%20%3D%208)
![5(3 - \frac{x}{5} ) = 5 \times 8](https://tex.z-dn.net/?f=5%283%20-%20%20%5Cfrac%7Bx%7D%7B5%7D%20%29%20%3D%205%20%5Ctimes%208)
![5 \times 3 - 5 \times \frac{x}{5} = 5 \times 8](https://tex.z-dn.net/?f=5%20%5Ctimes%203%20-%205%20%5Ctimes%20%20%5Cfrac%7Bx%7D%7B5%7D%20%20%3D%205%20%5Ctimes%208)
![15 - 5 \times \frac{x}{5} = 40](https://tex.z-dn.net/?f=15%20-%205%20%5Ctimes%20%20%5Cfrac%7Bx%7D%7B5%7D%20%20%3D%2040)
![15 - x = 40](https://tex.z-dn.net/?f=15%20-%20x%20%3D%2040)
![- x = 40 - 15](https://tex.z-dn.net/?f=%20-%20x%20%3D%2040%20-%2015)
![- x = 25](https://tex.z-dn.net/?f=%20-%20x%20%3D%2025)
![x = - 25](https://tex.z-dn.net/?f=x%20%3D%20%20-%2025)
1/4 because 0.25 is the same thing as 25/100. 25/100 simplified is 1/4