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3 years ago

A right triangle with a keg 3mi and hypotenuse 5mi

Mathematics

1 answer:

kolbaska11 [484]3 years ago

4 0

Answer:

Step-by-step explanation:

this is a famous triangle :) known as the 3-4-5 triangle...

it has an angle of 53.73... on the side with the 3

and an angle of 36.869... on the side with the 4

hope that helps with what ever the question is :)

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Whatbis the slope of a line that is perpendicular to the line y= 2x-6? A. -2

ICE Princess25 [194]

Answer:

D. -1/2

Step-by-step explanation:

When a line is perpendicular to another line the slope will be the exact opposite. For example line A = y = 3x + 5 the line perpendicular to it will be -1/3x.

So -1/2 is the slope of your perpendicular line.

4 0

3 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

aniked [119]

Answer:

$(b^4)^2 = b^{8}$

Step-by-step explanation:

Given

$(b^4)^2$

Required

Simplify

In indices, we have:

$(a^m)^n = a^{m*n$

So:

$(b^4)^2 = b^{4*2}$

$(b^4)^2 = b^{8}$

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3 years ago

Find m∠ABC = 7x - 4 and m∠BDC = 9x - 1 and and m∠ABC = 107°, find x, m∠ABC and m∠BDC.

Artyom0805 [142]

Answer:

m<BDC = 62 degrees

Step-by-step explanation:

Using the expression;

<ABC = <ABD + <DBC

107 = 7x-4 + 9x - 1

107 = 16x-5

16x = 107 + 5

16x = 112

x = 112/16

x = 7

Get m<DBC

m<BDC = 9x - 1

m<BDC = 9(7)-1

m<BDC = 63 - 1

m<BDC = 62 degrees

6 0

3 years ago

a football field team lost 9 yards during a play the team had a combined gain or loss of 0 yards after the next play.what intege

Nezavi [6.7K]

9!! hope this helps lol

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3 years ago

A bag contains 3 pink gumballs, 4 red gumballs, and 2 green gumballs. Find the probability that a red gumball is drawn if there

fgiga [73]

Answer:

0.99

Step-by-step explanation:

Given,

Pink gumballs = 3,

Red gumballs = 4,

Green gumballs = 2,

So, total gumballs = 3 + 4 + 2 = 9,

Thus, total ways of selecting 5 gumball = $^9C_5$

$=\frac{9!}{5!4!}$

$=\frac{9\times 8\times 7\times 6}{24}$

$=9\times 2\times 7$

$=126$

Also, the total ways of selecting no red gumballs = $^4C_0\times ^5C_5$

= 1 × 1

= 1

So, the probability of no red gumballs in 5 drawn

$=\frac{1}{126}$

Hence, the probability that a red gumball is drawn if there are 5 drawings

= 1 - probability of no red gumballs

$=1-\frac{1}{126}$

$=\frac{125}{126}$

≈ 0.99

8 0

3 years ago

Read 2 more answers