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3 years ago

9

find three consecutive even integers such that the sum of the least integer and the middle integer is 22 more than the greatest

integer

1 answer:

mrs_skeptik [129]3 years ago

7 0

Your integers are x, x+2, and x+4
x+x+2=22+x+4
2x+2=x+26
x=24
the integers are 24,26,28

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Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

we have

$y\leq \frac{4}{3}x+5$ ----> inequality A

$y\geq -\frac{5}{2}x+5$ ---> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

<u><em>Verify each point</em></u>

Substitute the value of x and the value of y of each ordered pair in the inequality A and in the inequality B

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therefore

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case 2) (0,3)

Inequality A

$3\leq \frac{4}{3}(0)+5$

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Inequality B

$3\geq -\frac{5}{2}(0)+5$

$3\geq 5$ ----> is not true

therefore

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$-6\leq \frac{4}{3}(-6)+5$

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therefore

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