Answer:
61.) A, B, A
62.) 120 minutes
Step-by-step explanation:
61.) 48 is a multiple of 6. A multiple is a number which can be fully divided into another number (divded without remainder). Therefore, 48 is a multiple of 6 because 6 * 8 = 48 meaning that 48/6 would equal 8. Because there is no remainder, Carly can put the beads into 6 equal groups.
62.) This is a simple conversion problem. Since they are asking the amount of minutes, you need to convert 2 hours to minutes. You do not need to calculate it or set up a formula because there are 60 minutes in one hour, therore, in 2 hours there are 120 minutes (60 minutes + 60 minutes).
Answer:
Do you want to be extremely boring?
Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?
is a valid solution.
Want something more fun? Why not a parabola?
.
At this point you have three parameters to play with, and from the fact that
we can already fix one of them, in particular
. At this point I would recommend picking an easy value for one of the two, let's say
(or even
, it will just flip everything upside down) and find out b accordingly:
Our function becomes
Notice that it works even by switching sign in the first two terms: 
Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: 
Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need
, and at that point the first condition is guaranteed; using the second to find k we get 

Or how about a sine wave that oscillates around 2? with a similar reasoning you get

Sky is the limit.
Solutions
To solve this problem we have to use the Pythagorean theorem. You can only use the Pythagorean theorem in Right Triangles. The longest side of the triangle is called the "hypotenuse". C² is the longest side so it is the hypotenuse . To calculate c² we have to do α² + β² = c².
Given
One leg of a right triangular piece of land has a length of 24 yards. They hypotenuse has a length of 74 yards. The other leg has a length of 10x yards.
First leg (24 yards) would be α
Second leg would be β
Hypotenuse (74 yards) would be c
Now we have points α β c.
a² (24) + β² ( x ) = c² (74)
Calculations
c² = α² + β²
74² = 24²+ β²
<span>5476 = 576 + </span>β²
5476 - 576 = β²
<span> </span>
<span>4900 = </span>β²
→√4900
<span> </span>
β<span> = 70 yards
</span>
<span>70 = 10x
</span>
<span>x = 70</span>÷<span>10 = 7 yards
</span>
The second leg = 7 yards
Answer:
you can fit 1000 hairs in 10 cm
Step-by-step explanation:

