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Nataly [62]
3 years ago
15

Find an angle a that is coterminal with an angle measuring −810∘, where 0∘≤a<360∘. Do not include the degree symbol in your a

nswer. For example, if your answer is 20∘, you would enter 20.
Mathematics
1 answer:
Brilliant_brown [7]3 years ago
4 0

-810 + 360 = -450

-450 + 360 = -90

-90 + 360 = 270

Answer: 270

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10.36 less than the product of 42 and x <br> please i need help
Brums [2.3K]

Answer:

so the problem is saying 42x-10.36 so it's just saying take 10.36 away from 42 multiplied by X

Step-by-step explanation:

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!
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Solving by an inequality is : x ≤ 130
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For what values of x is f(x) = |x + 1| differentiable? I'm struggling my butt off for this course
pav-90 [236]

By definition of absolute value, you have

f(x) = |x+1| = \begin{cases}x+1&\text{if }x+1\ge0 \\ -(x+1)&\text{if }x+1

or more simply,

f(x) = \begin{cases}x+1&\text{if }x\ge-1\\-x-1&\text{if }x

On their own, each piece is differentiable over their respective domains, except at the point where they split off.

For <em>x</em> > -1, we have

(<em>x</em> + 1)<em>'</em> = 1

while for <em>x</em> < -1,

(-<em>x</em> - 1)<em>'</em> = -1

More concisely,

f'(x) = \begin{cases}1&\text{if }x>-1\\-1&\text{if }x

Note the strict inequalities in the definition of <em>f '(x)</em>.

In order for <em>f(x)</em> to be differentiable at <em>x</em> = -1, the derivative <em>f '(x)</em> must be continuous at <em>x</em> = -1. But this is not the case, because the limits from either side of <em>x</em> = -1 for the derivative do not match:

\displaystyle \lim_{x\to-1^-}f'(x) = \lim_{x\to-1}(-1) = -1

\displaystyle \lim_{x\to-1^+}f'(x) = \lim_{x\to-1}1 = 1

All this to say that <em>f(x)</em> is differentiable everywhere on its domain, <em>except</em> at the point <em>x</em> = -1.

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Can you find the area for this?
Tanzania [10]

Answer:

b. is the right answer of your question

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3 years ago
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