<img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%2B%202x%20%2B%201%20" id="TexFormula1" title=" {x}^{2} + 2x + 1 " alt=

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aleksandrvk [35]

3 years ago

" {x}^{2} + 2x + 1 " align="absmiddle" class="latex-formula">

Mathematics

1 answer:

DanielleElmas [232]3 years ago

5 0

(x+1) ^2. So for this problem i learned the X factory in order to solve it. so what u. need to do is find a number(s) that multiply to 1. (the one on the far right is the one u multiply) and a those same numbers need to add to 2. so one and one multiply to one and add up to 2. so u do (x+1) (x+1) but since there the exact same u just put a little 2 up on the brackets

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3 years ago

X – 7y = –11 5x + 2y = -18

laiz [17]

Answer:

hope this help you

Step-by-step explanation:

Simplifying

X + -7y = -11

Solving

X + -7y = -11

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '7y' to each side of the equation.

X + -7y + 7y = -11 + 7y

Combine like terms: -7y + 7y = 0

X = -11 + 7y

Simplifying

X = -11 + 7y

------------------------------------------------------------------------------------------------------------

Solving

5x + 2y = -18

Solving for variable 'x'.

Add '-2y' to each side of the equation.

5x + 2y + -2y = -18 + -2y

Combine like terms: 2y + -2y = 0

5x = -18 + -2y

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Simplifying

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4 0

3 years ago

1)X²+5X-50=0 2)6²+6B-16=0 3)R²+6R+8=0 4)P²+5P+6=0

zubka84 [21]

1) X²+5X-50=0

↠X² + 10X -5X -50 = 0

↠X(X+10)-5(X+10) = 0

↠(X-5)(X+10)=0

↠X = 5, -10

2)B²+6B-16=0

↠B² + 8B - 2B -16 = 0

↠B(B+8) -2(B+8) =0

↠(B-2) (B+8) =0

↠B = 2,-8

3)R²+6R+8=0

↠R²+4R+2R+8=0

↠R(R+4)+2(R+4)=0

↠(R+2)(R+4)=0

↠R=-2,-4

4) P²+5P+6=0

↠P²+3P+2P+6=0

↠P(P+3)+2(P+3)=0

↠(P+2)(P+3)=0

↠P=-2,-3

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2 years ago

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