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3 years ago

What is the area of this figure 3,7,7

Mathematics

1 answer:

IRINA_888 [86]3 years ago

4 0

I think the answer is 147

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29+18+21 justify your steps

zhannawk [14.2K]

Add 29 and 18 first to get to get 47 then add 47 and 21 to get your final answer that is 68

5 0

3 years ago

Read 2 more answers

Find the volume of the figure. Round to the nearest tenth if necessary.<br> 3 yd<br> 3 yd<br> 10 yd

MrMuchimi

Answer: 90 yards

Step-by-step explanation:

10 by 3 by 3 is 90

4 0

3 years ago

What value of x makes the equation true?

Rasek [7]

<em>Greetings from Brasil...</em>

Let's add all the values on one side and make it equal to the sum of all the other values on the other side

(- X) + (- X) + (- X) + (- X) + (- X) + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 = X + X + X + (- 1) + (- 1) + (- 1) + (- 1) + (- 1) + (- 1) + (- 1) + (- 1)

- 5X + 12 = 3X - 8

- 5X - 3X = - 8 - 12

- 8X = - 20 x(- 1)

8X = 20

X = 20/8

3 0

3 years ago

If F(x) and 1(x) are inverse functions of each other and f(x) = 2x+5, what is (8)?

evablogger [386]

23 i used an app use should also give that a try

8 0

3 years ago

Read 2 more answers

If the ratio of the length of segment AC to the length of segment CB is 3:1, what is the y-coordinate of point C?

Yuki888 [10]

Answer:

The coordinates of point C are (8,8.5)

Step-by-step explanation:

The picture of the question in the attached figure

Let

$(C_x,C_y)$ ----> coordinates of point C

we have that

The horizontal distance AB is equal to

$AB_x=10-2=8\ units$

The vertical distance AB is equal to

$AB_y=10-4=6\ units$

Find the horizontal coordinate of point C

we know that

$\frac{AC}{CB}=\frac{3}{1}$

$\frac{AC_x}{CB_x}=\frac{3}{1}$

$AC_x=3CB_x$ ----> equation A

$AC_x+CB_x=8$ ----> equation B

substitute equation A in equation B

$3CB_x+CB_x=8$

$4CB_x=8\\CB_x=2$

$AC_x=3(2)=6$

The x-coordinate of point C is equal to the x-coordinate of point A plus the horizontal distance between the point A and point C

$C_x=A_x+AC_x=2+6=8$

Find the vertical coordinate of point C

we know that

$\frac{AC}{CB}=\frac{3}{1}$

$\frac{AC_y}{CB_y}=\frac{3}{1}$

$AC_y=3CB_y$ ----> equation A

$AC_y+CB_y=6$ ----> equation B

substitute equation A in equation B

$3CB_y+CB_y=6$

$4CB_y=6\\CB_y=1.5$

$AC_y=3(1.5)=4.5$

The y-coordinate of point C is equal to the y-coordinate of point A plus the vertical distance between the point A and point C

$C_y=A_y+AC_y=4+4.5=8.5$

therefore

The coordinates of point C are (8,8.5)

5 0

3 years ago